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∀ x0 x1 x2 x3 x4 . ap (lam 5 (λ x6 . If_i (x6 = 0) x0 (If_i (x6 = 1) x1 (If_i (x6 = 2) x2 (If_i (x6 = 3) x3 x4))))) 1 = x1
as obj
-
as prop
49b93..tuple_5_1_eq
theory
HotG
stx
70a36..
address
TMQcH..tuple_5_1_eq