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Proofgold Term Root Disambiguation

∀ x0 x1 x2 x3 . ap (lam 4 (λ x5 . If_i (x5 = 0) x0 (If_i (x5 = 1) x1 (If_i (x5 = 2) x2 x3)))) 1 = x1
as obj
-
as prop
bf73b..tuple_4_1_eq
theory
HotG
stx
a7e8b..
address
TMSYE..tuple_4_1_eq