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Proofgold Proof

pf
Claim L0: ∀ x0 . IrreflexiveSymmetricReln x0struct_r x0
Let x0 of type ι be given.
Apply H0 with struct_r x0.
Assume H1: struct_r x0.
Assume H2: unpack_r_o x0 (λ x1 . λ x2 : ι → ι → ο . and (∀ x3 . x3x1not (x2 x3 x3)) (∀ x3 . x3x1∀ x4 . x4x1x2 x3 x4x2 x4 x3)).
The subproof is completed by applying H1.
Claim L1: ∀ x0 x1 x2 x3 . IrreflexiveSymmetricReln x0IrreflexiveSymmetricReln x1BinRelnHom x0 x1 x2BinRelnHom x0 x1 x3IrreflexiveSymmetricReln (05907.. x0 x1 x2 x3)
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Assume H3: BinRelnHom x0 x1 x2.
Assume H4: BinRelnHom x0 x1 x3.
Apply unknownprop_034efb78ebb5063d16d232d7a2af450524a44508ccd003479f3d4a1b105247b8 with x0, λ x4 . IrreflexiveSymmetricReln (05907.. x4 x1 x2 x3) leaving 2 subgoals.
The subproof is completed by applying H1.
Let x4 of type ι be given.
Let x5 of type ιιο be given.
Assume H5: ∀ x6 . x6x4not (x5 x6 x6).
Assume H6: ∀ x6 . x6x4∀ x7 . x7x4x5 x6 x7x5 x7 x6.
Apply unknownprop_f1f0d0235cc3f72918ba3b7bc6e671feb556f667a17378616f96007dc95611ad with x4, x5, x1, x2, x3, λ x6 x7 . IrreflexiveSymmetricReln x7.
Apply unknownprop_d442b731cc8a623579f119dd4140f334acbb8f35c49c35a487654154f8239ef6 with {x6 ∈ x4|ap x2 x6 = ap x3 x6}, x5 leaving 2 subgoals.
Let x6 of type ι be given.
Assume H7: x6{x7 ∈ x4|ap x2 x7 = ap x3 x7}.
Apply H5 with x6.
Apply SepE1 with x4, λ x7 . ap x2 x7 = ap x3 x7, x6.
The subproof is completed by applying H7.
Let x6 of type ι be given.
Assume H7: x6{x7 ∈ x4|ap x2 x7 = ap x3 x7}.
Let x7 of type ι be given.
Assume H8: x7{x8 ∈ x4|ap x2 x8 = ap x3 x8}.
Assume H9: x5 x6 x7.
Apply H6 with x6, x7 leaving 3 subgoals.
Apply SepE1 with x4, λ x8 . ap x2 x8 = ap x3 x8, x6.
The subproof is completed by applying H7.
Apply SepE1 with x4, λ x8 . ap x2 x8 = ap x3 x8, x7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
Apply unknownprop_2aabccf4699c9f902dcc37be8ad1f3aaa001e5f2bb081556c38a4bbd69d3e5c6 with IrreflexiveSymmetricReln leaving 2 subgoals.
The subproof is completed by applying L0.
The subproof is completed by applying L1.