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Proofgold Proof

pf
Let x0 of type ιιο be given.
Assume H0: ∀ x1 x2 . x0 x1 x2x0 x2 x1.
Assume H1: not (∃ x1 . and (x1u9) (and (equip u4 x1) (∀ x2 . x2x1∀ x3 . x3x1(x2 = x3∀ x4 : ο . x4)not (x0 x2 x3)))).
Let x1 of type ι be given.
Assume H2: x1u9.
Let x2 of type ι be given.
Assume H3: x2u9.
Let x3 of type ι be given.
Assume H4: x3u9.
Let x4 of type ι be given.
Assume H5: x4u9.
Assume H6: not (x0 x1 x2).
Assume H7: not (x0 x1 x3).
Assume H8: not (x0 x1 x4).
Assume H9: not (x0 x2 x3).
Assume H10: not (x0 x2 x4).
Assume H11: not (x0 x3 x4).
Let x5 of type ο be given.
Assume H12: x1 = x2x5.
Assume H13: x1 = x3x5.
Assume H14: x1 = x4x5.
Assume H15: x2 = x3x5.
Assume H16: x2 = x4x5.
Assume H17: x3 = x4x5.
Claim L18: ...
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Apply dneg with x5.
Assume H19: not x5.
Claim L20: ...
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Apply H1.
Let x6 of type ο be given.
Assume H21: ∀ x7 . and (x7u9) (and (equip u4 x7) (∀ x8 . x8x7∀ x9 . x9x7(x8 = x9∀ x10 : ο . x10)not (x0 x8 x9)))x6.
Apply H21 with SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4.
Apply andI with SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4u9, and (equip u4 (SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4)) (∀ x7 . x7SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4∀ x8 . x8SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4(x7 = x8∀ x9 : ο . x9)not (x0 x7 x8)) leaving 2 subgoals.
Let x7 of type ι be given.
Assume H22: x7SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4.
Apply L20 with x7, λ x8 . x8u9 leaving 5 subgoals.
The subproof is completed by applying H22.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
Apply andI with equip u4 (SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4), ∀ x7 . x7SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4∀ x8 . x8SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4(x7 = x8∀ x9 : ο . x9)not (x0 x7 x8) leaving 2 subgoals.
Apply equip_sym with SetAdjoin (SetAdjoin (UPair x1 x2) x3) x4, u4.
Apply unknownprop_30f51c1e2b83590a7ed46a006f5e6311b01e639f1f6e9abb0eccefd285a20a15 with x1, x2, x3, x4 leaving 6 subgoals.
Assume H22: x1 = x2.
Apply H19.
Apply H12.
The subproof is completed by applying H22.
Assume H22: ....
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