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Proofgold Proof

pf
Let x0 of type ιι be given.
Let x1 of type ιιι be given.
Let x2 of type ιο be given.
Let x3 of type ιι be given.
Let x4 of type ιιι be given.
Let x5 of type ιιο be given.
Let x6 of type ιι be given.
Let x7 of type ιιι be given.
Let x8 of type ι be given.
Let x9 of type ιι be given.
Let x10 of type ιι be given.
Let x11 of type ι be given.
Let x12 of type ι be given.
Let x13 of type ι be given.
Let x14 of type ιι be given.
Let x15 of type ιιι be given.
Let x16 of type ιιιι be given.
Let x17 of type ιιο be given.
Let x18 of type ιιιι be given.
Let x19 of type ιιι be given.
Assume H0: ∀ x20 x21 x22 . (x21 = x19 x20 x22False)x17 (x18 x20 x22 x21) x21x17 (x18 x20 x22 x21) x20False.
Assume H1: ∀ x20 x21 x22 . (x21 = x19 x22 x20False)x17 (x18 x22 x20 x21) x21x17 (x18 x22 x20 x21) x20False.
Assume H2: ∀ x20 x21 x22 . (x21 = x19 x20 x22False)(x17 (x18 x20 x22 x21) x21False)(x17 (x18 x20 x22 x21) x22False)(x17 (x18 x20 x22 x21) x20False)False.
Assume H3: ∀ x20 x21 x22 . (x21 = x0 x22False)x17 x20 x22x17 (x1 x22 x21) x20x17 (x1 x22 x21) x21False.
Assume H4: ∀ x20 x21 x22 . (x17 (x16 x20 x21 x22) x20False)x21 = x0 x20x17 x22 x21False.
Assume H5: ∀ x20 x21 x22 . (x17 x22 (x16 x20 x21 x22)False)x21 = x0 x20x17 x22 x21False.
Assume H6: ∀ x20 x21 . (x21 = x0 x20False)(x17 (x1 x20 x21) x21False)(x17 (x1 x20 x21) (x15 x20 x21)False)False.
Assume H7: ∀ x20 x21 . (x2 x21False)x17 x20 (x3 x21)x5 (x4 x21 x20) x21False.
Assume H8: ∀ x20 x21 x22 . (x2 x22False)(x5 x20 x22False)(x17 x21 (x3 x22)False)x17 x20 x21x17 x21 (x0 x22)False.
Assume H9: ∀ x20 x21 . (x2 x21False)(x5 x20 x21False)(x17 x20 (x6 x21)False)x17 x20 (x0 (x0 x21))False.
Assume H10: ∀ x20 x21 . (x21 = x0 x20False)(x17 (x1 x20 x21) x21False)(x17 (x15 x20 x21) x20False)False.
Assume H11: ∀ x20 x21 x22 . (x5 x22 (x19 x21 x20)False)x5 x22 x20x5 x22 x21False.
Assume H12: ∀ x20 x21 x22 . (x5 ... ...False)x5 x21 (x19 x22 x20)False.
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