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Proofgold Proof

pf
Let x0 of type ο be given.
Let x1 of type ο be given.
Let x2 of type ο be given.
Assume H0: exactly1of3 x0 x1 x2.
Apply exactly1of3_E with x0, x1, x2, not x1 ⟶ or x0 x2 leaving 4 subgoals.
The subproof is completed by applying H0.
Assume H1: x0.
Assume H2: not x1.
Assume H3: not x2.
Assume H4: not x1.
Apply orIL with x0, x2.
The subproof is completed by applying H1.
Assume H1: not x0.
Assume H2: x1.
Assume H3: not x2.
Assume H4: not x1.
Apply H4 with or x0 x2.
The subproof is completed by applying H2.
Assume H1: not x0.
Assume H2: not x1.
Assume H3: x2.
Assume H4: not x1.
Apply orIR with x0, x2.
The subproof is completed by applying H3.
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