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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Assume H0: CSNo x0.
Assume H1: CSNo x1.
Assume H2: CSNo x2.
set y3 to be mul_CSNo x0 (mul_CSNo x1 x2)
set y4 to be mul_CSNo y3 (mul_CSNo x1 x2)
Claim L3: ∀ x5 : ι → ο . x5 y4x5 y3
Let x5 of type ιο be given.
Assume H3: x5 (mul_CSNo y4 (mul_CSNo x2 y3)).
set y6 to be mul_CSNo x2 (mul_CSNo y3 y4)
set y7 to be mul_CSNo y3 (mul_CSNo x5 y4)
Claim L4: ∀ x8 : ι → ο . x8 y7x8 y6
Let x8 of type ιο be given.
Assume H4: x8 (mul_CSNo y4 (mul_CSNo y6 x5)).
set y9 to be λ x9 . x8
Apply mul_CSNo_com with x5, y6, λ x10 x11 . y9 (mul_CSNo y4 x10) (mul_CSNo y4 x11) leaving 3 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H4.
set y8 to be λ x8 . y7
Apply L4 with λ x9 . y8 x9 y7y8 y7 x9 leaving 2 subgoals.
Assume H5: y8 y7 y7.
The subproof is completed by applying H5.
Apply mul_CSNo_assoc with x5, y7, y6, λ x9 . y8 leaving 4 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H2.
set y9 to be mul_CSNo (mul_CSNo x5 y7) y6
set y10 to be mul_CSNo (mul_CSNo y8 y6) y7
Claim L5: ∀ x11 : ι → ο . x11 y10x11 y9
Let x11 of type ιο be given.
Assume H5: x11 (mul_CSNo (mul_CSNo y9 y7) y8).
set y12 to be λ x12 . x11
Apply mul_CSNo_com with y7, y9, λ x13 x14 . y12 (mul_CSNo x13 y8) (mul_CSNo x14 y8) leaving 3 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H5.
set y11 to be λ x11 . y10
Apply L5 with λ x12 . y11 x12 y10y11 y10 x12 leaving 2 subgoals.
Assume H6: y11 y10 y10.
The subproof is completed by applying H6.
set y12 to be λ x12 . y11
Apply mul_CSNo_assoc with y10, y8, y9, λ x13 x14 . y12 x14 x13 leaving 4 subgoals.
The subproof is completed by applying L4.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying L5.
Let x5 of type ιιο be given.
Apply L3 with λ x6 . x5 x6 y4x5 y4 x6.
Assume H4: x5 y4 y4.
The subproof is completed by applying H4.