Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι → ι be given.
Let x3 of type ι → ι be given.
Let x4 of type ι → ι → ο be given.
Let x5 of type ι → ι → ο be given.
Apply unknownprop_ff14fe4b2b5ebb9a364ac3d2b72652c556f881650361e9e04e15eb4f78727558 with
73737.. x0 x2 x4,
x1,
x3,
x5.
The subproof is completed by applying H0.
Claim L2: x0 = x1
Apply L1 with
λ x6 x7 . x0 = x7.
The subproof is completed by applying unknownprop_56fff63ae4aaffa24f98b7fb5e034afaf3bd48ea6cf337512ab94a8fb832e90d with x0, x2, x4.
Apply and3I with
x0 = x1,
∀ x6 . prim1 x6 x0 ⟶ x2 x6 = x3 x6,
∀ x6 . prim1 x6 x0 ⟶ ∀ x7 . prim1 x7 x0 ⟶ x4 x6 x7 = x5 x6 x7 leaving 3 subgoals.
The subproof is completed by applying L2.
Let x6 of type ι be given.
Apply unknownprop_0eba4a1e8a6eb85bd93458d64288a202dddf6558775b796d073829b1ed4aed10 with
x0,
x2,
x4,
x6,
λ x7 x8 . x8 = x3 x6 leaving 2 subgoals.
The subproof is completed by applying H3.
Apply L2 with
λ x7 x8 . prim1 x6 x7.
The subproof is completed by applying H3.
Apply H0 with
λ x7 x8 . f482f.. (f482f.. x8 (4ae4a.. 4a7ef..)) x6 = x3 x6.
Let x7 of type ι → ι → ο be given.
Apply unknownprop_0eba4a1e8a6eb85bd93458d64288a202dddf6558775b796d073829b1ed4aed10 with
x1,
x3,
x5,
x6,
λ x8 x9 . x7 x9 x8.
The subproof is completed by applying L4.
Let x6 of type ι be given.
Let x7 of type ι be given.
Apply unknownprop_d3745c59fd830feec1cf172211f6f2a659a425d7b1b42063659cffa5062c6422 with
x0,
x2,
x4,
x6,
x7,
λ x8 x9 : ο . x9 = x5 x6 x7 leaving 3 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
Apply L2 with
λ x8 x9 . prim1 x6 x8.
The subproof is completed by applying H3.
Apply L2 with
λ x8 x9 . prim1 x7 x8.
The subproof is completed by applying H4.
Apply H0 with
λ x8 x9 . 2b2e3.. (f482f.. x9 (4ae4a.. (4ae4a.. 4a7ef..))) x6 x7 = x5 x6 x7.
Let x8 of type ο → ο → ο be given.
Apply unknownprop_d3745c59fd830feec1cf172211f6f2a659a425d7b1b42063659cffa5062c6422 with
x1,
x3,
x5,
x6,
x7,
λ x9 x10 : ο . x8 x10 x9 leaving 2 subgoals.
The subproof is completed by applying L5.
The subproof is completed by applying L6.