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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιι be given.
Let x2 of type ιιιι be given.
Let x3 of type ιιο be given.
Assume H0: ∀ x4 . x4x0∀ x5 . tuple_p (x1 x4) x5∀ x6 : ι → ι . (∀ x7 . x7x1 x4c40a3.. x0 x1 x2 (ap x5 x7) (x6 x7))(∀ x7 . x7x1 x4x3 (ap x5 x7) (x6 x7))x3 (lam 2 (λ x7 . If_i (x7 = 0) x4 x5)) (x2 x4 x5 (lam (x1 x4) (λ x7 . x6 x7))).
Claim L1: ∀ x4 x5 . c40a3.. x0 x1 x2 x4 x5and (c40a3.. x0 x1 x2 x4 x5) (x3 x4 x5)
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H1: c40a3.. x0 x1 x2 x4 x5.
Apply H1 with λ x6 x7 . and (c40a3.. x0 x1 x2 x6 x7) (x3 x6 x7).
Let x6 of type ι be given.
Assume H2: x6x0.
Let x7 of type ι be given.
Assume H3: tuple_p (x1 x6) x7.
Let x8 of type ιι be given.
Assume H4: ∀ x9 . x9x1 x6and (c40a3.. x0 x1 x2 (ap x7 x9) (x8 x9)) (x3 (ap x7 x9) (x8 x9)).
Apply andI with c40a3.. x0 x1 x2 (lam 2 (λ x9 . If_i (x9 = 0) x6 x7)) (x2 x6 x7 (lam (x1 x6) x8)), x3 (lam 2 (λ x9 . If_i (x9 = 0) x6 x7)) (x2 x6 x7 (lam (x1 x6) x8)) leaving 2 subgoals.
Apply unknownprop_412f171b3ca442889854b1b6db1f4b4c229650705be86611715b49239feb0217 with x0, x1, x2, x6, x7, x8 leaving 3 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Let x9 of type ι be given.
Assume H5: x9x1 x6.
Apply H4 with x9, c40a3.. x0 x1 x2 (ap x7 x9) (x8 x9) leaving 2 subgoals.
The subproof is completed by applying H5.
Assume H6: c40a3.. x0 x1 x2 (ap x7 x9) (x8 x9).
Assume H7: x3 (ap x7 x9) (x8 x9).
The subproof is completed by applying H6.
Apply H0 with x6, x7, x8 leaving 4 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Let x9 of type ι be given.
Assume H5: x9x1 x6.
Apply H4 with x9, c40a3.. x0 x1 x2 (ap x7 x9) (x8 x9) leaving 2 subgoals.
The subproof is completed by applying H5.
Assume H6: c40a3.. x0 x1 x2 (ap x7 x9) (x8 x9).
Assume H7: x3 (ap x7 x9) ....
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Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H2: c40a3.. x0 x1 x2 x4 x5.
Apply L1 with x4, x5, x3 x4 x5 leaving 2 subgoals.
The subproof is completed by applying H2.
Assume H3: c40a3.. x0 x1 x2 x4 x5.
Assume H4: x3 x4 x5.
The subproof is completed by applying H4.