Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
set y3 to be ...
Claim L5: ∀ x5 : ι → ο . x5 y4 ⟶ x5 y3
Let x5 of type ι → ο be given.
Claim L6: ∀ x8 : ι → ο . x8 y7 ⟶ x8 y6
Let x8 of type ι → ο be given.
set y9 to be λ x9 . x8
Apply mul_SNo_zeroL with
y6,
λ x10 x11 . y9 (add_SNo x10 (mul_SNo y4 x5)) (add_SNo x11 (mul_SNo y4 x5)) leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H6.
set y8 to be λ x8 . y7
Apply L6 with
λ x9 . y8 x9 y7 ⟶ y8 y7 x9 leaving 2 subgoals.
Assume H7: y8 y7 y7.
The subproof is completed by applying H7.
Apply add_SNo_0L with
mul_SNo x5 y6,
λ x9 . y8 leaving 2 subgoals.
Apply SNo_mul_SNo with
x5,
y6 leaving 2 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying L6.
Let x5 of type ι → ι → ο be given.
Apply L5 with
λ x6 . x5 x6 y4 ⟶ x5 y4 x6.
Assume H6: x5 y4 y4.
The subproof is completed by applying H6.
Claim L6: ∀ x5 : ι → ο . x5 y4 ⟶ x5 y3
Let x5 of type ι → ο be given.
Claim L7: ∀ x8 : ι → ο . x8 y7 ⟶ x8 y6
Let x8 of type ι → ο be given.
set y9 to be λ x9 . x8
Apply mul_SNo_zeroL with
x5,
λ x10 x11 . y9 (add_SNo (mul_SNo y4 y6) x10) (add_SNo (mul_SNo y4 y6) x11) leaving 2 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H7.
set y8 to be λ x8 . y7
Apply L7 with
λ x9 . y8 x9 y7 ⟶ y8 y7 x9 leaving 2 subgoals.
Assume H8: y8 y7 y7.
The subproof is completed by applying H8.
Apply add_SNo_0R with
mul_SNo x5 y7,
λ x9 . y8 leaving 2 subgoals.
Apply SNo_mul_SNo with
x5,
y7 leaving 2 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H4.
The subproof is completed by applying L7.
Let x5 of type ι → ι → ο be given.
Apply L6 with
λ x6 . x5 x6 y4 ⟶ x5 y4 x6.
Assume H7: x5 y4 y4.
The subproof is completed by applying H7.
Apply L5 with
λ x3 x4 . SNoLt x3 (mul_SNo x0 x2).
Apply L6 with
λ x3 x4 . SNoLt (add_SNo (mul_SNo 0 x2) (mul_SNo x0 x1)) x3.
Apply mul_SNo_Lt with
x0,
x2,
0,
x1 leaving 6 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H3.
The subproof is completed by applying SNo_0.
The subproof is completed by applying H2.
The subproof is completed by applying H1.
The subproof is completed by applying H4.