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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Apply beta with 10, λ x10 . If_i (x10 = 0) x0 (If_i (x10 = 1) x1 (If_i (x10 = 2) x2 (If_i (x10 = 3) x3 (If_i (x10 = 4) x4 (If_i (x10 = 5) x5 (If_i (x10 = 6) x6 (If_i (x10 = 7) x7 (If_i (x10 = 8) x8 x9)))))))), 8, λ x10 x11 . x11 = x8 leaving 2 subgoals.
The subproof is completed by applying unknownprop_afbf689bc11c7ff9c9e9875ca76148f88a08e7b5261e935945ff12d04ab37d90.
Apply If_i_0 with 8 = 0, x0, If_i (8 = 1) x1 (If_i (8 = 2) x2 (If_i (8 = 3) x3 (If_i (8 = 4) x4 (If_i (8 = 5) x5 (If_i (8 = 6) x6 (If_i (8 = 7) x7 (If_i (8 = 8) x8 x9))))))), λ x10 x11 . x11 = x8 leaving 2 subgoals.
The subproof is completed by applying neq_8_0.
Apply If_i_0 with 8 = 1, x1, If_i (8 = 2) x2 (If_i (8 = 3) x3 (If_i (8 = 4) x4 (If_i (8 = 5) x5 (If_i (8 = 6) x6 (If_i (8 = 7) x7 (If_i (8 = 8) x8 x9)))))), λ x10 x11 . x11 = x8 leaving 2 subgoals.
The subproof is completed by applying neq_8_1.
Apply If_i_0 with 8 = 2, x2, If_i (8 = 3) x3 (If_i (8 = 4) x4 (If_i (8 = 5) x5 (If_i (8 = 6) x6 (If_i (8 = 7) x7 (If_i (8 = 8) x8 x9))))), λ x10 x11 . x11 = x8 leaving 2 subgoals.
The subproof is completed by applying neq_8_2.
Apply If_i_0 with 8 = 3, x3, If_i (8 = 4) x4 (If_i (8 = 5) x5 (If_i (8 = 6) x6 (If_i (8 = 7) x7 (If_i (8 = 8) x8 x9)))), λ x10 x11 . x11 = x8 leaving 2 subgoals.
The subproof is completed by applying neq_8_3.
Apply If_i_0 with 8 = 4, x4, If_i (8 = 5) x5 (If_i (8 = 6) x6 (If_i (8 = 7) x7 (If_i (8 = 8) x8 x9))), λ x10 x11 . x11 = x8 leaving 2 subgoals.
The subproof is completed by applying neq_8_4.
Apply If_i_0 with 8 = 5, x5, If_i (8 = 6) x6 (If_i (8 = 7) x7 (If_i (8 = 8) x8 x9)), λ x10 x11 . x11 = x8 leaving 2 subgoals.
The subproof is completed by applying neq_8_5.
Apply If_i_0 with 8 = 6, x6, If_i (8 = 7) x7 ..., ... leaving 2 subgoals.
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