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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Assume H0: x2setexp x1 x0.
Let x3 of type ι be given.
Assume H1: x3setexp x1 x0.
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H2: 3897e.. x0 x2 x3 x4 x5.
Apply H2 with λ x6 x7 . iff (x6x1) (x7x1) leaving 4 subgoals.
Let x6 of type ι be given.
Assume H3: x6x0.
Apply iffI with ap x2 x6x1, ap x3 x6x1 leaving 2 subgoals.
Assume H4: ap x2 x6x1.
Apply ap_Pi with x0, λ x7 . x1, x3, x6 leaving 2 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
Assume H4: ap x3 x6x1.
Apply ap_Pi with x0, λ x7 . x1, x2, x6 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H3.
Let x6 of type ι be given.
The subproof is completed by applying iff_refl with x6x1.
Let x6 of type ι be given.
Let x7 of type ι be given.
Assume H3: iff (x6x1) (x7x1).
Apply iff_sym with x6x1, x7x1.
The subproof is completed by applying H3.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Assume H3: iff (x6x1) (x7x1).
Assume H4: iff (x7x1) (x8x1).
Apply iff_trans with x6x1, x7x1, x8x1 leaving 2 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H4.