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Proofgold Proof

pf
Let x0 of type ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → CN (ιι) be given.
Claim L0: ChurchNums_8_perm_0_7_6_5_4_3_2_1 = λ x1 : ((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)(ι → ι)ι → ι . λ x2 x3 x4 x5 x6 x7 x8 x9 : (ι → ι)ι → ι . x1 x2 x9 x8 x7 x6 x5 x4 x3
Let x1 of type ((((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → CN (ιι)) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → CN (ιι)) → ((((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → CN (ιι)) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → CN (ιι)) → ο be given.
Assume H0: x1 ChurchNums_8_perm_0_7_6_5_4_3_2_1 (λ x2 : ((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)(ι → ι)ι → ι . λ x3 x4 x5 x6 x7 x8 x9 x10 : (ι → ι)ι → ι . x2 x3 x10 x9 x8 x7 x6 x5 x4).
The subproof is completed by applying H0.
Apply L0 with λ x1 x2 : (((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)(ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)(ι → ι)ι → ι . (λ x3 x4 x5 x6 x7 x8 x9 x10 : (ι → ι)ι → ι . x2 x0 x3 x10 x9 x8 x7 x6 x5 x4) = x0.
Let x1 of type (((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → CN (ιι)) → (((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → ((ιι) → ιι) → CN (ιι)) → ο be given.
Assume H1: x1 (λ x2 x3 x4 x5 x6 x7 x8 x9 : (ι → ι)ι → ι . (λ x10 : ((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)((ι → ι)ι → ι)(ι → ι)ι → ι . λ x11 x12 x13 x14 x15 x16 x17 x18 : (ι → ι)ι → ι . x10 x11 x18 x17 x16 x15 x14 x13 x12) x0 x2 x9 x8 x7 x6 x5 x4 x3) x0.
The subproof is completed by applying H1.