Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Let x10 of type ι be given.
Let x11 of type ι be given.
Let x12 of type ι be given.
Let x13 of type ι be given.
Let x14 of type ι be given.
Let x15 of type ι be given.
Let x16 of type ι be given.
Let x17 of type ι be given.
Let x18 of type ι be given.
Let x19 of type ι be given.
Let x20 of type ι be given.
Let x21 of type ι be given.
Let x22 of type ι be given.
Let x23 of type ι be given.
Apply idl_negcycle_12 with
x0,
x1,
x2,
x3,
x4,
x5,
x6,
x7,
x8,
x9,
x10,
x11,
minus_SNo x12,
minus_SNo x13,
minus_SNo x14,
minus_SNo x15,
minus_SNo x16,
minus_SNo x17,
minus_SNo x18,
minus_SNo x19,
minus_SNo x20,
minus_SNo x21,
minus_SNo x22,
minus_SNo x23 leaving 37 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
The subproof is completed by applying H11.
The subproof is completed by applying L37.
The subproof is completed by applying L38.
The subproof is completed by applying L39.
The subproof is completed by applying L40.
The subproof is completed by applying L41.
The subproof is completed by applying L42.
The subproof is completed by applying L43.
The subproof is completed by applying L44.
The subproof is completed by applying L45.
The subproof is completed by applying L46.
The subproof is completed by applying L47.
The subproof is completed by applying L48.
Apply minus_SNo_Lt_contra3 with
0,
add_SNo (minus_SNo x12) (add_SNo (minus_SNo x13) (add_SNo (minus_SNo x14) (add_SNo (minus_SNo x15) (add_SNo (minus_SNo x16) (add_SNo (minus_SNo x17) (add_SNo (minus_SNo x18) (add_SNo (minus_SNo x19) (add_SNo (minus_SNo x20) (add_SNo (minus_SNo x21) (add_SNo (minus_SNo x22) (minus_SNo x23))))))))))) leaving 3 subgoals.
The subproof is completed by applying SNo_0.
Apply SNo_add_SNo_12 with
minus_SNo x12,
...,
...,
...,
...,
...,
...,
...,
...,
...,
...,
... leaving 12 subgoals.