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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Apply set_ext with setsum x0 x1, lam 2 (λ x2 . If_i (x2 = 0) x0 x1) leaving 2 subgoals.
Let x2 of type ι be given.
Assume H0: x2setsum x0 x1.
Apply pairE with x0, x1, x2, x2lam 2 (λ x3 . If_i (x3 = 0) x0 x1) leaving 3 subgoals.
The subproof is completed by applying H0.
Assume H1: ∃ x3 . and (x3x0) (x2 = setsum 0 x3).
Apply exandE_i with λ x3 . x3x0, λ x3 . x2 = setsum 0 x3, x2lam 2 (λ x3 . If_i (x3 = 0) x0 x1) leaving 2 subgoals.
The subproof is completed by applying H1.
Let x3 of type ι be given.
Assume H2: x3x0.
Assume H3: x2 = setsum 0 x3.
Apply H3 with λ x4 x5 . x5lam 2 (λ x6 . If_i (x6 = 0) x0 x1).
Apply lamI with 2, λ x4 . If_i (x4 = 0) x0 x1, 0, x3 leaving 2 subgoals.
The subproof is completed by applying In_0_2.
Apply If_i_1 with 0 = 0, x0, x1, λ x4 x5 . x3x5 leaving 2 subgoals.
Let x4 of type ιιο be given.
Assume H4: x4 0 0.
The subproof is completed by applying H4.
The subproof is completed by applying H2.
Assume H1: ∃ x3 . and (x3x1) (x2 = setsum 1 x3).
Apply exandE_i with λ x3 . x3x1, λ x3 . x2 = setsum 1 x3, x2lam 2 (λ x3 . If_i (x3 = 0) x0 x1) leaving 2 subgoals.
The subproof is completed by applying H1.
Let x3 of type ι be given.
Assume H2: x3x1.
Assume H3: x2 = setsum 1 x3.
Apply H3 with λ x4 x5 . x5lam 2 (λ x6 . If_i (x6 = 0) x0 x1).
Apply lamI with 2, λ x4 . If_i (x4 = 0) x0 x1, 1, x3 leaving 2 subgoals.
The subproof is completed by applying In_1_2.
Apply If_i_0 with 1 = 0, x0, x1, λ x4 x5 . x3x5 leaving 2 subgoals.
The subproof is completed by applying neq_1_0.
The subproof is completed by applying H2.
Let x2 of type ι be given.
Assume H0: x2lam 2 (λ x3 . If_i (x3 = 0) x0 x1).
Claim L1: ...
...
Apply exandE_i with λ x3 . x32, λ x3 . ∃ x4 . and (x4If_i (x3 = 0) x0 x1) (x2 = setsum x3 x4), x2setsum x0 x1 leaving 2 subgoals.
The subproof is completed by applying L1.
Let x3 of type ι be given.
Assume H2: x32.
Assume H3: ∃ x4 . and (x4If_i (x3 = 0) x0 x1) (x2 = setsum x3 x4).
Apply exandE_i with λ x4 . x4If_i (x3 = 0) x0 x1, λ x4 . x2 = setsum x3 x4, x2setsum x0 x1 leaving 2 subgoals.
The subproof is completed by applying H3.
Let x4 of type ι be given.
Assume H4: x4If_i (x3 = 0) x0 x1.
Assume H5: x2 = setsum x3 x4.
Apply H5 with λ x5 x6 . x6....
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