Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι → ι → ι be given.
Let x4 of type ι → ι → ι be given.
Let x5 of type ι be given.
Apply explicit_Field_minus_clos with
x0,
x1,
x2,
x3,
x4,
x5 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Apply explicit_Field_minus_clos with
x0,
x1,
x2,
x3,
x4,
explicit_Field_minus x0 x1 x2 x3 x4 x5 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying L2.
Apply explicit_Field_plus_cancelL with
x0,
x1,
x2,
x3,
x4,
explicit_Field_minus x0 x1 x2 x3 x4 x5,
explicit_Field_minus x0 x1 x2 x3 x4 (explicit_Field_minus x0 x1 x2 x3 x4 x5),
x5 leaving 5 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying L2.
The subproof is completed by applying L3.
The subproof is completed by applying H1.
Apply explicit_Field_minus_L with
x0,
x1,
x2,
x3,
x4,
x5,
λ x6 x7 . x3 (explicit_Field_minus x0 x1 x2 x3 x4 x5) (explicit_Field_minus x0 x1 x2 x3 x4 (explicit_Field_minus x0 x1 x2 x3 x4 x5)) = x7 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Apply explicit_Field_minus_R with
x0,
x1,
x2,
x3,
x4,
explicit_Field_minus x0 x1 x2 x3 x4 x5 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying L2.