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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Apply unknownprop_c5e2164052a280ad5b04f622e53815f0267ee33361e4345305e43303abef2c1b with 7, λ x7 . If_i (x7 = 0) x0 (If_i (x7 = 1) x1 (If_i (x7 = 2) x2 (If_i (x7 = 3) x3 (If_i (x7 = 4) x4 (If_i (x7 = 5) x5 x6))))), 1, λ x7 x8 . x8 = x1 leaving 2 subgoals.
The subproof is completed by applying unknownprop_0e67950fcbb0031a20447924ec54669bb62163d4c596516dd4a14bc1dfb67db7.
Apply unknownprop_5a150bd86f4285de5d98c60b17d4452a655b4d88de0a02247259cdad6e6d992c with 1 = 0, x0, If_i (1 = 1) x1 (If_i (1 = 2) x2 (If_i (1 = 3) x3 (If_i (1 = 4) x4 (If_i (1 = 5) x5 x6)))), λ x7 x8 . x8 = x1 leaving 2 subgoals.
The subproof is completed by applying unknownprop_698eb914d3aabc70ca0bb946b6907a27e3cce6e39040426b924e77df3507fbcf.
Apply unknownprop_6f44febdf8a865ee94133af873e3c2941a931de6ac80968301360290e02ca608 with 1 = 1, x1, If_i (1 = 2) x2 (If_i (1 = 3) x3 (If_i (1 = 4) x4 (If_i (1 = 5) x5 x6))).
Let x7 of type ιιο be given.
Assume H0: x7 1 1.
The subproof is completed by applying H0.