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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ιι be given.
Let x3 of type ι be given.
Let x4 of type ιιι be given.
Apply explicit_Nats_E with x0, x1, x2, ∀ x5 . x5x0∀ x6 . c3e2e.. x0 x1 x2 x3 x4 (x2 x5) x6∃ x7 . and (x6 = x4 x5 x7) (c3e2e.. x0 x1 x2 x3 x4 x5 x7).
Assume H0: explicit_Nats x0 x1 x2.
Assume H1: x1x0.
Assume H2: ∀ x5 . x5x0x2 x5x0.
Assume H3: ∀ x5 . x5x0x2 x5 = x1∀ x6 : ο . x6.
Assume H4: ∀ x5 . x5x0∀ x6 . x6x0x2 x5 = x2 x6x5 = x6.
Assume H5: ∀ x5 : ι → ο . x5 x1(∀ x6 . x5 x6x5 (x2 x6))∀ x6 . x6x0x5 x6.
Claim L6: ...
...
Claim L7: ∀ x5 . ...∀ x6 . ...(λ x7 x8 . and (c3e2e.. x0 x1 x2 x3 x4 x7 x8) (∀ x9 . ...x7 = ...∃ x10 . and (x8 = x4 x9 x10) (c3e2e.. x0 x1 x2 x3 x4 x9 x10))) ... ...
...
Let x5 of type ι be given.
Assume H8: x5x0.
Let x6 of type ι be given.
Assume H9: c3e2e.. x0 x1 x2 x3 x4 (x2 x5) x6.
Claim L10: ∀ x7 . x7x0x2 x5 = x2 x7∃ x8 . and (x6 = x4 x7 x8) (c3e2e.. x0 x1 x2 x3 x4 x7 x8)
Apply H9 with λ x7 x8 . and (c3e2e.. x0 x1 x2 x3 x4 x7 x8) (∀ x9 . x9x0x7 = x2 x9∃ x10 . and (x8 = x4 x9 x10) (c3e2e.. x0 x1 x2 x3 x4 x9 x10)), ∀ x7 . x7x0x2 x5 = x2 x7∃ x8 . and (x6 = x4 x7 x8) (c3e2e.. x0 x1 x2 x3 x4 x7 x8) leaving 3 subgoals.
The subproof is completed by applying L6.
The subproof is completed by applying L7.
Assume H10: c3e2e.. x0 x1 x2 x3 x4 (x2 x5) x6.
Assume H11: ∀ x7 . x7x0x2 x5 = x2 x7∃ x8 . and (x6 = x4 x7 x8) (c3e2e.. x0 x1 x2 x3 x4 x7 x8).
The subproof is completed by applying H11.
Apply L10 with x5 leaving 2 subgoals.
The subproof is completed by applying H8.
Let x7 of type ιιο be given.
Assume H11: x7 (x2 x5) (x2 x5).
The subproof is completed by applying H11.