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Proofgold Proof

pf
Apply unknownprop_1ecba3dd5eafa4f5c4681522469f6140788e091a78ad9f01e97cc0b6f2c0488f with ordsucc, nat_p, λ x0 . add_nat 83 x0, 2, λ x0 x1 . x1 = 149 leaving 4 subgoals.
The subproof is completed by applying nat_ordsucc.
The subproof is completed by applying add_nat_SR with 83.
The subproof is completed by applying nat_2.
Apply add_nat_SR with 83, 1, λ x0 x1 . ChurchNum_ii_6 ChurchNum2 ordsucc x1 = 149 leaving 2 subgoals.
The subproof is completed by applying nat_1.
Apply add_nat_SR with 83, 0, λ x0 x1 . ChurchNum_ii_6 ChurchNum2 ordsucc (ordsucc x1) = 149 leaving 2 subgoals.
The subproof is completed by applying nat_0.
Apply add_nat_0R with 83, λ x0 x1 . ChurchNum_ii_6 ChurchNum2 ordsucc (ordsucc (ordsucc x1)) = 149.
Let x0 of type ι → ι → ο be given.
Assume H0: x0 (ChurchNum_ii_6 ChurchNum2 ordsucc 85) 149.
The subproof is completed by applying H0.
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