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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιι be given.
Let x2 of type ιι be given.
Assume H0: ∀ x3 . In x3 x0In (x2 x3) (x1 x3).
Apply unknownprop_1a1eed9c2e0652a509eabe7b8f07e31768cab0357ad1d97cb464202e3d371a17 with x0, λ x3 . x1 x3, lam x0 (λ x3 . x2 x3) leaving 2 subgoals.
Let x3 of type ι be given.
Assume H1: In x3 (lam x0 (λ x4 . x2 x4)).
Claim L2: ∃ x4 . and (In x4 x0) (∃ x5 . and (In x5 (x2 x4)) (x3 = setsum x4 x5))
Apply unknownprop_f25818182af6b093121a8b5d43847162c8ea91396e524cca02557613a430a57a with x0, x2, x3.
The subproof is completed by applying H1.
Apply unknownprop_3848cfb1fd522cb609408da39f227a9c05924a24919f21041d0880590b824ef5 with λ x4 . In x4 x0, λ x4 . ∃ x5 . and (In x5 (x2 x4)) (x3 = setsum x4 x5), and (setsum_p x3) (In (ap x3 0) x0) leaving 2 subgoals.
The subproof is completed by applying L2.
Let x4 of type ι be given.
Assume H3: In x4 x0.
Assume H4: ∃ x5 . and (In x5 (x2 x4)) (x3 = setsum x4 x5).
Apply unknownprop_3848cfb1fd522cb609408da39f227a9c05924a24919f21041d0880590b824ef5 with λ x5 . In x5 (x2 x4), λ x5 . x3 = setsum x4 x5, and (setsum_p x3) (In (ap x3 0) x0) leaving 2 subgoals.
The subproof is completed by applying H4.
Let x5 of type ι be given.
Assume H5: In x5 (x2 x4).
Assume H6: x3 = setsum x4 x5.
Apply unknownprop_389e2fb1855352fcc964ea44fe6723d7a1c2d512f04685300e3e97621725b977 with setsum_p x3, In (ap x3 0) x0 leaving 2 subgoals.
Apply H6 with λ x6 x7 . setsum_p x7.
The subproof is completed by applying unknownprop_f61ccefc6bc57eb6c116b3bc3f27a552fe11c91770c4e9cfa989285bab91c3f5 with x4, x5.
Apply H6 with λ x6 x7 . In (ap x7 0) x0.
Apply unknownprop_4ec3261e93b098949bcb767ddc18dfeab1e68ae68e2b47fdb55e525983415999 with x4, x5, λ x6 x7 . In x7 x0.
The subproof is completed by applying H3.
Let x3 of type ι be given.
Assume H1: In x3 x0.
Apply unknownprop_c5e2164052a280ad5b04f622e53815f0267ee33361e4345305e43303abef2c1b with x0, x2, x3, λ x4 x5 . In x5 (x1 x3) leaving 2 subgoals.
The subproof is completed by applying H1.
Apply H0 with x3.
The subproof is completed by applying H1.