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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: x1int.
Let x2 of type ι be given.
Assume H1: x2int.
Assume H2: divides_int x0 (add_SNo x1 (minus_SNo x2)).
Claim L3: minus_SNo (add_SNo x1 (minus_SNo x2)) = add_SNo x2 (minus_SNo x1)
Apply add_SNo_com with x1, minus_SNo x2, λ x3 x4 . minus_SNo x4 = add_SNo x2 (minus_SNo x1) leaving 3 subgoals.
Apply int_SNo with x1.
The subproof is completed by applying H0.
Apply SNo_minus_SNo with x2.
Apply int_SNo with x2.
The subproof is completed by applying H1.
Apply minus_add_SNo_distr with minus_SNo x2, x1, λ x3 x4 . x4 = add_SNo x2 (minus_SNo x1) leaving 3 subgoals.
Apply SNo_minus_SNo with x2.
Apply int_SNo with x2.
The subproof is completed by applying H1.
Apply int_SNo with x1.
The subproof is completed by applying H0.
Apply minus_SNo_invol with x2, λ x3 x4 . add_SNo x4 (minus_SNo x1) = add_SNo x2 (minus_SNo x1) leaving 2 subgoals.
Apply int_SNo with x2.
The subproof is completed by applying H1.
Let x3 of type ιιο be given.
Assume H3: x3 (add_SNo x2 (minus_SNo x1)) (add_SNo x2 (minus_SNo x1)).
The subproof is completed by applying H3.
Apply L3 with λ x3 x4 . divides_int x0 x3.
Apply divides_int_minus_SNo with x0, add_SNo x1 (minus_SNo x2).
The subproof is completed by applying H2.