Search for blocks/addresses/...

Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: SNo x0.
Apply SNoLtLe_or with x0, 0, abs_SNo (minus_SNo x0) = abs_SNo x0 leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying SNo_0.
Assume H1: SNoLt x0 0.
Apply neg_abs_SNo with x0, λ x1 x2 . abs_SNo (minus_SNo x0) = x2 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Claim L2: SNoLe 0 (minus_SNo x0)
Apply SNoLtLe with 0, minus_SNo x0.
Apply minus_SNo_Lt_contra2 with x0, 0 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying SNo_0.
Apply minus_SNo_0 with λ x1 x2 . SNoLt x0 x2.
The subproof is completed by applying H1.
Apply nonneg_abs_SNo with minus_SNo x0.
The subproof is completed by applying L2.
Assume H1: SNoLe 0 x0.
Apply SNoLtLe_or with minus_SNo x0, 0, abs_SNo (minus_SNo x0) = abs_SNo x0 leaving 4 subgoals.
Apply SNo_minus_SNo with x0.
The subproof is completed by applying H0.
The subproof is completed by applying SNo_0.
Assume H2: SNoLt (minus_SNo x0) 0.
Apply nonneg_abs_SNo with x0, λ x1 x2 . abs_SNo (minus_SNo x0) = x2 leaving 2 subgoals.
The subproof is completed by applying H1.
Apply neg_abs_SNo with minus_SNo x0, λ x1 x2 . x2 = x0 leaving 3 subgoals.
Apply SNo_minus_SNo with x0.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
Apply minus_SNo_invol with x0.
The subproof is completed by applying H0.
Assume H2: SNoLe 0 (minus_SNo x0).
Claim L3: x0 = 0
Apply SNoLe_antisym with x0, 0 leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying SNo_0.
Apply minus_SNo_0 with λ x1 x2 . SNoLe x0 x1.
Apply minus_SNo_invol with x0, λ x1 x2 . SNoLe x1 (minus_SNo 0) leaving 2 subgoals.
The subproof is completed by applying H0.
Apply minus_SNo_Le_contra with 0, minus_SNo x0 leaving 3 subgoals.
The subproof is completed by applying SNo_0.
Apply SNo_minus_SNo with x0.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
The subproof is completed by applying H1.
Apply L3 with λ x1 x2 . abs_SNo (minus_SNo x2) = abs_SNo x2.
set y1 to be abs_SNo (minus_SNo 0)
set y2 to be abs_SNo 0
Claim L4: ∀ x3 : ι → ο . x3 y2x3 y1
Let x3 of type ιο be given.
Assume H4: x3 (abs_SNo 0).
set y4 to be λ x4 . x3
Apply minus_SNo_0 with λ x5 x6 . y4 (abs_SNo x5) (abs_SNo x6).
The subproof is completed by applying H4.
Let x3 of type ιιο be given.
Apply L4 with λ x4 . x3 x4 y2x3 y2 x4.
Assume H5: x3 y2 y2.
The subproof is completed by applying H5.