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Apply nat_ind with λ x0 . ∀ x1 . nat_p x1 ⟶ x0 ⊆ x1 ⟶ ∃ x2 . and (nat_p x2) (x1 = add_nat x2 x0) leaving 2 subgoals.
Let x0 of type ι be given.
Assume H1: 0 ⊆ x0.
Let x1 of type ο be given.
Apply H2 with x0.
Apply andI with nat_p x0, x0 = add_nat x0 0 leaving 2 subgoals.
The subproof is completed by applying H0.
Let x2 of type ι → ι → ο be given.
The subproof is completed by applying add_nat_0R with x0, λ x3 x4 . x2 x4 x3.
Let x0 of type ι be given.
Apply nat_inv_impred with λ x1 . ordsucc x0 ⊆ x1 ⟶ ∃ x2 . and (nat_p x2) (x1 = add_nat x2 (ordsucc x0)) leaving 2 subgoals.
Apply FalseE with ∃ x1 . and (nat_p x1) (0 = add_nat x1 (ordsucc x0)).
Apply EmptyE with x0.
Apply H2 with x0.
The subproof is completed by applying ordsuccI2 with x0.
Let x1 of type ι be given.
Apply H1 with x1, ∃ x2 . and (nat_p x2) (ordsucc x1 = add_nat x2 (ordsucc x0)) leaving 3 subgoals.
The subproof is completed by applying H2.
Apply ordinal_In_Or_Subq with x1, x0, x0 ⊆ x1 leaving 4 subgoals.
Apply nat_p_ordinal with x1.
The subproof is completed by applying H2.
Apply nat_p_ordinal with x0.
The subproof is completed by applying H0.
Assume H4: x1 ∈ x0.
Apply FalseE with x0 ⊆ x1.
Apply In_irref with ordsucc x1.
Apply H3 with ordsucc x1.
Apply nat_ordsucc_in_ordsucc with x0, x1 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H4.
Assume H4: x0 ⊆ x1.
The subproof is completed by applying H4.
Let x2 of type ι be given.
Apply H4 with ∃ x3 . and (nat_p x3) (ordsucc x1 = add_nat x3 (ordsucc x0)).
Let x3 of type ο be given.
Apply H7 with x2.
Apply andI with nat_p x2, ordsucc x1 = add_nat x2 (ordsucc x0) leaving 2 subgoals.
The subproof is completed by applying H5.
Apply add_nat_SR with x2, x0, λ x4 x5 . ordsucc x1 = x5 leaving 2 subgoals.
The subproof is completed by applying H0.
Claim L8: ∀ x5 : ι → ο . x5 y4 ⟶ x5 (ordsucc x1)
Let x5 of type ι → ο be given.
The subproof is completed by applying H6 with λ x6 x7 . (λ x8 . x5) (ordsucc x6) (ordsucc x7).
Let x5 of type ι → ι → ο be given.
Apply L8 with λ x6 . x5 x6 y4 ⟶ x5 y4 x6.
Assume H9: x5 y4 y4.
The subproof is completed by applying H9.
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