Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Apply H0 with
divides_int x0 (mul_SNo x1 x2) ⟶ or (divides_int x0 x1) (divides_int x0 x2).
Assume H3:
and (x0 ∈ omega) (1 ∈ x0).
Apply H3 with
(∀ x3 . x3 ∈ omega ⟶ divides_nat x3 x0 ⟶ or (x3 = 1) (x3 = x0)) ⟶ divides_int x0 (mul_SNo x1 x2) ⟶ or (divides_int x0 x1) (divides_int x0 x2).
Assume H4:
x0 ∈ omega.
Assume H5: 1 ∈ x0.
Apply xm with
divides_int x0 x1,
or (divides_int x0 x1) (divides_int x0 x2) leaving 2 subgoals.
Apply orIR with
divides_int x0 x1,
divides_int x0 x2.
Apply BezoutThm with
x0,
x1,
1,
divides_int x0 x2 leaving 4 subgoals.
The subproof is completed by applying L9.
The subproof is completed by applying H1.
Assume H11:
and (x0 = 0) (x1 = 0).
Apply H11 with
False.
Assume H12: x0 = 0.
Assume H13: x1 = 0.
Apply In_no2cycle with
0,
1 leaving 2 subgoals.
The subproof is completed by applying In_0_1.
Apply H12 with
λ x3 x4 . 1 ∈ x3.
The subproof is completed by applying H5.
Apply H11 with
divides_int x0 x2 leaving 2 subgoals.
Apply and3I with
divides_int 1 x0,
divides_int 1 x1,
∀ x3 . divides_int x3 x0 ⟶ divides_int x3 x1 ⟶ SNoLe x3 1 leaving 3 subgoals.
Apply divides_int_1 with
x0.
The subproof is completed by applying L9.
Apply divides_int_1 with
x1.
The subproof is completed by applying H1.
Let x3 of type ι be given.
Apply H13 with
SNoLe x3 1.
Apply H15 with
SNoLe x3 1.
Apply SNoLtLe_or with
x3,
0,
SNoLe x3 1 leaving 4 subgoals.
Apply int_SNo with
x3.
The subproof is completed by applying H17.
The subproof is completed by applying SNo_0.
Apply SNoLtLe with
x3,
1.
Apply SNoLt_tra with
x3,
0,
1 leaving 5 subgoals.
Apply int_SNo with
x3.
The subproof is completed by applying H17.
The subproof is completed by applying SNo_0.
The subproof is completed by applying SNo_1.