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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Apply unknownprop_b456609235d152f08bccfce314d541d7c44f3716137c00b0ce21cf467ba83d17 with 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))))), λ x6 . If_i (x6 = 4a7ef..) x0 (If_i (x6 = 4ae4a.. 4a7ef..) x1 (If_i (x6 = 4ae4a.. (4ae4a.. 4a7ef..)) x2 (If_i (x6 = 4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))) x3 (If_i (x6 = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) x4 x5)))), 4ae4a.. (4ae4a.. 4a7ef..), λ x6 x7 . x7 = x2 leaving 2 subgoals.
The subproof is completed by applying unknownprop_4c53365541c997f532d46b55d7f585d28389a2866aa833a3fec1f9d90c28059b.
Apply If_i_0 with 4ae4a.. (4ae4a.. 4a7ef..) = 4a7ef.., x0, If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. 4a7ef..) x1 (If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. 4a7ef..)) x2 (If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))) x3 (If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) x4 x5))), λ x6 x7 . x7 = x2 leaving 2 subgoals.
The subproof is completed by applying unknownprop_38b5b92bfd131ef0428a8ee212f746419349b56c1e9077ab24b3c25647caace1.
Apply If_i_0 with 4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. 4a7ef.., x1, If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. 4a7ef..)) x2 (If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))) x3 (If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) x4 x5)), λ x6 x7 . x7 = x2 leaving 2 subgoals.
The subproof is completed by applying unknownprop_e0e602efce8c3fbbb791d74669e968feb76e9d28b29f3878aea98e1fe1efe584.
Apply If_i_1 with 4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. 4a7ef..), x2, If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..))) x3 (If_i (4ae4a.. (4ae4a.. 4a7ef..) = 4ae4a.. (4ae4a.. (4ae4a.. (4ae4a.. 4a7ef..)))) x4 x5).
Let x6 of type ιιο be given.
Assume H0: x6 (4ae4a.. (4ae4a.. 4a7ef..)) (4ae4a.. (4ae4a.. 4a7ef..)).
The subproof is completed by applying H0.