Let x0 of type ι → ο be given.
Let x1 of type ι → ι → ι be given.
Assume H0: ∀ x2 x3 . x0 x2 ⟶ x0 x3 ⟶ x0 (x1 x2 x3).
Assume H1: ∀ x2 x3 x4 . x0 x2 ⟶ x0 x3 ⟶ x0 x4 ⟶ x1 x2 (x1 x3 x4) = x1 x3 (x1 x2 x4).
Assume H2: ∀ x2 x3 . x0 x2 ⟶ x0 x3 ⟶ x1 x2 x3 = x1 x3 x2.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Assume H3: x0 x2.
Assume H4: x0 x3.
Assume H5: x0 x4.
Assume H6: x0 x5.
Assume H7: x0 x6.
Assume H8: x0 x7.
Assume H9: x0 x8.
Assume H10: x0 x9.
Apply unknownprop_9b08836e02c4ecab23ffe407c500b75674d8128928669b1aa1e6670ede61d6f8 with
x0,
x1,
x3,
x4,
x5,
x6,
x7,
x8,
x9,
λ x10 x11 . x1 x2 x11 = x1 x6 (x1 x2 (x1 x7 (x1 x4 (x1 x5 (x1 x8 (x1 x9 x3)))))) leaving 10 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
Apply H2 with
x3,
x9,
λ x10 x11 . x1 x2 (x1 x4 (x1 x5 (x1 x6 (x1 x7 (x1 x8 x11))))) = x1 x6 (x1 x2 (x1 x7 (x1 x4 (x1 x5 (x1 x8 (x1 x9 x3)))))) leaving 3 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying H10.
Apply unknownprop_c7a5ce18a43642e92566eaac1f11466ec2cdad1d372f890cc5f913370407cb11 with
x0,
x1,
x2,
x4,
x5,
x6,
x7,
x1 x8 (x1 x9 x3) leaving 8 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
Apply H0 with
x8,
x1 x9 x3 leaving 2 subgoals.
The subproof is completed by applying H9.
Apply H0 with
x9,
x3 leaving 2 subgoals.
The subproof is completed by applying H10.
The subproof is completed by applying H4.