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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: SNo x0.
Assume H1: SNo x1.
Assume H2: SNoLt x0 x1.
Apply minus_SNo_prop1 with x0, SNoLt (minus_SNo x1) (minus_SNo x0) leaving 2 subgoals.
The subproof is completed by applying H0.
Assume H3: and (and (SNo (minus_SNo x0)) (∀ x2 . x2SNoL x0SNoLt (minus_SNo x0) (minus_SNo x2))) (∀ x2 . x2SNoR x0SNoLt (minus_SNo x2) (minus_SNo x0)).
Apply H3 with SNoCutP (prim5 (SNoR x0) minus_SNo) (prim5 (SNoL x0) minus_SNo)SNoLt (minus_SNo x1) (minus_SNo x0).
Assume H4: and (SNo (minus_SNo x0)) (∀ x2 . x2SNoL x0SNoLt (minus_SNo x0) (minus_SNo x2)).
Apply H4 with (∀ x2 . x2SNoR x0SNoLt (minus_SNo x2) (minus_SNo x0))SNoCutP (prim5 (SNoR x0) minus_SNo) (prim5 (SNoL x0) minus_SNo)SNoLt (minus_SNo x1) (minus_SNo x0).
Assume H5: SNo (minus_SNo x0).
Assume H6: ∀ x2 . x2SNoL x0SNoLt (minus_SNo x0) (minus_SNo x2).
Assume H7: ∀ x2 . x2SNoR x0SNoLt (minus_SNo x2) (minus_SNo x0).
Assume H8: SNoCutP (prim5 (SNoR x0) minus_SNo) (prim5 (SNoL x0) minus_SNo).
Apply minus_SNo_prop1 with x1, SNoLt (minus_SNo x1) (minus_SNo x0) leaving 2 subgoals.
The subproof is completed by applying H1.
Assume H9: and (and (SNo (minus_SNo x1)) (∀ x2 . x2SNoL x1SNoLt (minus_SNo x1) (minus_SNo x2))) (∀ x2 . x2SNoR x1SNoLt (minus_SNo x2) (minus_SNo x1)).
Apply H9 with SNoCutP (prim5 (SNoR x1) minus_SNo) (prim5 (SNoL x1) minus_SNo)SNoLt (minus_SNo x1) (minus_SNo x0).
Assume H10: and (SNo (minus_SNo x1)) (∀ x2 . x2SNoL x1SNoLt (minus_SNo x1) (minus_SNo x2)).
Apply H10 with (∀ x2 . x2SNoR x1SNoLt (minus_SNo x2) (minus_SNo x1))SNoCutP (prim5 (SNoR x1) minus_SNo) (prim5 (SNoL x1) minus_SNo)SNoLt (minus_SNo x1) (minus_SNo x0).
Assume H11: SNo (minus_SNo x1).
Assume H12: ∀ x2 . x2SNoL x1SNoLt (minus_SNo x1) (minus_SNo x2).
Assume H13: ∀ x2 . x2SNoR x1SNoLt (minus_SNo x2) (minus_SNo x1).
Assume H14: SNoCutP (prim5 (SNoR x1) minus_SNo) (prim5 (SNoL x1) minus_SNo).
Apply SNoLtE with x0, x1, SNoLt (minus_SNo x1) (minus_SNo x0) leaving 6 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
Let x2 of type ι be given.
Assume H15: SNo x2.
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