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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιο be given.
Let x2 of type ιο be given.
Apply unknownprop_d3eaeaf2c92929364f7d313ca2b01dbaa8e7169d84112bc61a6ed9c6cb0d624a with λ x3 x4 : ι → (ι → ο)(ι → ο) → ο . x4 x0 x1 x2∀ x5 : ο . (∀ x6 . In x6 x0PNoEq_ x6 x1 x2not (x1 x6)x2 x6x5)x5.
Assume H0: (λ x3 . λ x4 x5 : ι → ο . ∃ x6 . and (In x6 x3) (and (and (PNoEq_ x6 x4 x5) (not (x4 x6))) (x5 x6))) x0 x1 x2.
Let x3 of type ο be given.
Assume H1: ∀ x4 . In x4 x0PNoEq_ x4 x1 x2not (x1 x4)x2 x4x3.
Apply H0 with x3.
Let x4 of type ι be given.
Assume H2: (λ x5 . and (In x5 x0) (and (and (PNoEq_ x5 x1 x2) (not (x1 x5))) (x2 x5))) x4.
Apply andE with In x4 x0, and (and (PNoEq_ x4 x1 x2) (not (x1 x4))) (x2 x4), x3 leaving 2 subgoals.
The subproof is completed by applying H2.
Assume H3: In x4 x0.
Assume H4: and (and (PNoEq_ x4 x1 x2) (not (x1 x4))) (x2 x4).
Apply unknownprop_1eb28f5831a9d21e218b89c238edbbf849d22045bb77ce7cec926a651d1793f0 with PNoEq_ x4 x1 x2, not (x1 x4), x2 x4, x3 leaving 2 subgoals.
The subproof is completed by applying H4.
Assume H5: PNoEq_ x4 x1 x2.
Assume H6: not (x1 x4).
Assume H7: x2 x4.
Apply H1 with x4 leaving 4 subgoals.
The subproof is completed by applying H3.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.