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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιι be given.
Assume H0: ∀ x2 x3 . x0 x2x0 x3x0 (x1 x2 x3).
Assume H1: ∀ x2 x3 x4 . x0 x2x0 x3x0 x4x1 x2 (x1 x3 x4) = x1 x3 (x1 x2 x4).
Assume H2: ∀ x2 x3 . x0 x2x0 x3x1 x2 x3 = x1 x3 x2.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Assume H3: x0 x2.
Assume H4: x0 x3.
Assume H5: x0 x4.
Assume H6: x0 x5.
Assume H7: x0 x6.
Assume H8: x0 x7.
Assume H9: x0 x8.
Assume H10: x0 x9.
Apply unknownprop_515047c02fed97c50f69ea07f84c55a116d5435d48e441446058ba601add8797 with x0, x1, x4, x5, x6, x7, x8, x9, λ x10 x11 . x1 x2 (x1 x3 x11) = x1 x8 (x1 x6 (x1 x9 (x1 x2 (x1 x3 (x1 x7 (x1 x5 x4)))))) leaving 9 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
Apply H2 with x4, x9, λ x10 x11 . x1 x2 (x1 x3 (x1 x5 (x1 x6 (x1 x7 (x1 x8 x11))))) = x1 x8 (x1 x6 (x1 x9 (x1 x2 (x1 x3 (x1 x7 (x1 x5 x4)))))) leaving 3 subgoals.
The subproof is completed by applying H5.
The subproof is completed by applying H10.
Apply unknownprop_269e6ac5d03a8e6a992786f035ac6ed26040304e5a24360b92cc739aa05574ce with x0, x1, x2, x3, x5, x6, x7, x8, x9, x4 leaving 10 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
The subproof is completed by applying H5.