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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type (ιι) → ο be given.
Assume H0: ∀ x2 : ι → ι . x1 x2∀ x3 . x0 x3x0 (x2 x3).
Assume H1: ∀ x2 x3 : ι → ι . x1 x2x1 x3∀ x4 . x0 x4x2 (x3 x4) = x3 (x2 x4).
Let x2 of type ιι be given.
Let x3 of type ιι be given.
Let x4 of type ιι be given.
Let x5 of type ιι be given.
Let x6 of type ιι be given.
Let x7 of type ιι be given.
Let x8 of type ιι be given.
Let x9 of type ιι be given.
Let x10 of type ιι be given.
Let x11 of type ιι be given.
Assume H2: x1 x2.
Assume H3: x1 x3.
Assume H4: x1 x4.
Assume H5: x1 x5.
Assume H6: x1 x6.
Assume H7: x1 x7.
Assume H8: x1 x8.
Assume H9: x1 x9.
Assume H10: x1 x10.
Assume H11: x1 x11.
Let x12 of type ι be given.
Assume H12: x0 x12.
Apply H1 with x2, x3, x4 (x5 (x6 (x7 (x8 (x9 (x10 (x11 x12))))))) leaving 3 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Apply unknownprop_6998f1967a37ce79bf145b799234d391f8f1c42a3dd1f19ca25be7477a1f0225 with x0, x1, x11, x10, x9, x8, x7, x6, x5, x4, x12 leaving 10 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H11.
The subproof is completed by applying H10.
The subproof is completed by applying H9.
The subproof is completed by applying H8.
The subproof is completed by applying H7.
The subproof is completed by applying H6.
The subproof is completed by applying H5.
The subproof is completed by applying H4.
The subproof is completed by applying H12.