Let x0 of type ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι be given.
Let x1 of type ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι be given.
Let x2 of type ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι be given.
Let x3 of type ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι be given.
Let x4 of type ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι be given.
Assume H5: x0 = x1 ⟶ ∀ x5 : ο . x5.
Assume H6: x0 = x2 ⟶ ∀ x5 : ο . x5.
Assume H7: x0 = x3 ⟶ ∀ x5 : ο . x5.
Assume H8: x0 = x4 ⟶ ∀ x5 : ο . x5.
Assume H9: x1 = x2 ⟶ ∀ x5 : ο . x5.
Assume H10: x1 = x3 ⟶ ∀ x5 : ο . x5.
Assume H11: x1 = x4 ⟶ ∀ x5 : ο . x5.
Assume H12: x2 = x3 ⟶ ∀ x5 : ο . x5.
Assume H13: x2 = x4 ⟶ ∀ x5 : ο . x5.
Assume H14: x3 = x4 ⟶ ∀ x5 : ο . x5.
Apply unknownprop_37c1c08bb86d5b4e33948419b156e3861ea73d89bb0a60079717ef1ce7fe0047 with
x0,
False leaving 2 subgoals.
The subproof is completed by applying H0.
Let x5 of type (ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι) → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι be given.
Let x6 of type (ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι) → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι be given.
Assume H25:
∀ x7 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . Church13_p x7 ⟶ Church13_p (x5 x7).
Assume H26:
∀ x7 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . Church13_p x7 ⟶ Church13_p (x6 x7).
Assume H27: ∀ x7 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . x5 (x6 x7) = x7.
Assume H28: ∀ x7 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . x6 (x5 x7) = x7.
Assume H30: x5 x0 = λ x7 x8 x9 x10 x11 x12 x13 x14 x15 x16 x17 x18 x19 . x7.
Apply unknownprop_1ac6c2cb709c59fcef720a9dd88a74b82d0a33f832e6c8c08d3d6a9c6beaa8b4 with
x5 x1,
x5 x2,
x5 x3,
x5 x4 leaving 24 subgoals.
Apply H25 with
x1.
The subproof is completed by applying H1.
Apply H25 with
x2.
The subproof is completed by applying H2.
Apply H25 with
x3.
The subproof is completed by applying H3.
Apply H25 with
x4.
The subproof is completed by applying H4.
Apply H30 with
λ x7 x8 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . x7 = x5 x1 ⟶ ∀ x9 : ο . x9.
Assume H31: x5 x0 = x5 x1.
Apply H5.
Apply H28 with
x0,
λ x7 x8 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . x7 = x1.
Apply H28 with
x1,
λ x7 x8 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . x6 (x5 x0) = x7.
set y7 to be x6 (x5 x0)
set y8 to be y7 (x6 x2)
Claim L32: ∀ x9 : (ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι) → ο . x9 y8 ⟶ x9 y7
Let x9 of type (ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι) → ο be given.
Assume H32: x9 (y8 (y7 x3)).
set y10 to be λ x10 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . x9
Apply H31 with
λ x11 x12 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . y10 (y8 x11) (y8 x12).
The subproof is completed by applying H32.
Let x9 of type (ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι) → (ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι) → ο be given.
Apply L32 with
λ x10 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . x9 x10 y8 ⟶ x9 y8 x10.
Assume H33: x9 y8 y8.
The subproof is completed by applying H33.
Apply H30 with
λ x7 x8 : ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι → ι . ... ⟶ ∀ x9 : ο . x9.