Search for blocks/addresses/...

Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιιι be given.
Let x2 of type ι be given.
Assume H0: 42a91.. (96158.. x0 x1 x2).
Apply H0 with λ x3 . x3 = 96158.. x0 x1 x2prim1 x2 x0 leaving 2 subgoals.
Let x3 of type ι be given.
Let x4 of type ιιι be given.
Assume H1: ∀ x5 . prim1 x5 x3∀ x6 . prim1 x6 x3prim1 (x4 x5 x6) x3.
Let x5 of type ι be given.
Assume H2: prim1 x5 x3.
Assume H3: 96158.. x3 x4 x5 = 96158.. x0 x1 x2.
Apply unknownprop_1750497f7e7e39b522dc009c3dc9d7efa4738afbea22e7af55e0e833b2e30ad0 with x3, x0, x4, x1, x5, x2, prim1 x2 x0 leaving 2 subgoals.
The subproof is completed by applying H3.
Assume H4: and (x3 = x0) (∀ x6 . prim1 x6 x3∀ x7 . prim1 x7 x3x4 x6 x7 = x1 x6 x7).
Apply H4 with x5 = x2prim1 x2 x0.
Assume H5: x3 = x0.
Assume H6: ∀ x6 . prim1 x6 x3∀ x7 . prim1 x7 x3x4 x6 x7 = x1 x6 x7.
Assume H7: x5 = x2.
Apply H5 with λ x6 x7 . prim1 x2 x6.
Apply H7 with λ x6 x7 . prim1 x6 x3.
The subproof is completed by applying H2.
Let x3 of type ιιο be given.
Assume H1: x3 (96158.. x0 x1 x2) (96158.. x0 x1 x2).
The subproof is completed by applying H1.