Search for blocks/addresses/...

Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιιι be given.
Assume H0: 30750.. (987b2.. x0 x1).
Apply H0 with λ x2 . x2 = 987b2.. x0 x1∀ x3 . prim1 x3 x0∀ x4 . prim1 x4 x0prim1 (x1 x3 x4) x0 leaving 2 subgoals.
Let x2 of type ι be given.
Let x3 of type ιιι be given.
Assume H1: ∀ x4 . prim1 x4 x2∀ x5 . prim1 x5 x2prim1 (x3 x4 x5) x2.
Assume H2: 987b2.. x2 x3 = 987b2.. x0 x1.
Apply unknownprop_5cd05a110f3bf2a31b9390cadb44d05e7c4e54bd01cb3a1cbe102c4d216d9b84 with x2, x0, x3, x1, ∀ x4 . prim1 x4 x0∀ x5 . prim1 x5 x0prim1 (x1 x4 x5) x0 leaving 2 subgoals.
The subproof is completed by applying H2.
Assume H3: x2 = x0.
Assume H4: ∀ x4 . prim1 x4 x2∀ x5 . prim1 x5 x2x3 x4 x5 = x1 x4 x5.
Apply H3 with λ x4 x5 . ∀ x6 . prim1 x6 x4∀ x7 . prim1 x7 x4prim1 (x1 x6 x7) x4.
Let x4 of type ι be given.
Assume H5: prim1 x4 x2.
Let x5 of type ι be given.
Assume H6: prim1 x5 x2.
Apply H4 with x4, x5, λ x6 x7 . prim1 x6 x2 leaving 3 subgoals.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
Apply H1 with x4, x5 leaving 2 subgoals.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
Let x2 of type ιιο be given.
Assume H1: x2 (987b2.. x0 x1) (987b2.. x0 x1).
The subproof is completed by applying H1.