Let x0 of type ι → ο be given.
Let x1 of type ι → ι → ι be given.
Assume H0: ∀ x2 x3 . x0 x2 ⟶ x0 x3 ⟶ x0 (x1 x2 x3).
Assume H1: ∀ x2 x3 x4 . x0 x2 ⟶ x0 x3 ⟶ x0 x4 ⟶ x1 x2 (x1 x3 x4) = x1 x3 (x1 x2 x4).
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Assume H2: x0 x2.
Assume H3: x0 x3.
Assume H4: x0 x4.
Assume H5: x0 x5.
Assume H6: x0 x6.
Assume H7: x0 x7.
Assume H8: x0 x8.
Assume H9: x0 x9.
Apply unknownprop_01b85a5229069244bfc0fa2496398b6a876770b04992bb705aa6f0b7bd0f95bd with
x0,
x1,
x3,
x4,
x5,
x6,
x7,
x8,
x9,
λ x10 x11 . x1 x2 x11 = x1 x5 (x1 x2 (x1 x8 (x1 x6 (x1 x7 (x1 x3 (x1 x4 x9)))))) leaving 10 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
Apply H1 with
x2,
x5,
x1 x6 (x1 x7 (x1 x8 (x1 x3 (x1 x4 x9)))),
λ x10 x11 . x11 = x1 x5 (x1 x2 (x1 x8 (x1 x6 (x1 x7 (x1 x3 (x1 x4 x9)))))) leaving 4 subgoals.
The subproof is completed by applying H2.
The subproof is completed by applying H5.
Apply H0 with
x6,
x1 x7 (x1 x8 (x1 x3 (x1 x4 x9))) leaving 2 subgoals.
The subproof is completed by applying H6.
Apply H0 with
x7,
x1 x8 (x1 x3 (x1 x4 x9)) leaving 2 subgoals.
The subproof is completed by applying H7.
Apply H0 with
x8,
x1 x3 (x1 x4 x9) leaving 2 subgoals.
The subproof is completed by applying H8.
Apply H0 with
x3,
x1 x4 x9 leaving 2 subgoals.
The subproof is completed by applying H3.
Apply H0 with
x4,
x9 leaving 2 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying H9.
set y10 to be ...
set y11 to be ...
Claim L10: ∀ x12 : ι → ο . x12 y11 ⟶ x12 y10
Let x12 of type ι → ο be given.
Assume H10: x12 (x3 x7 (x3 x4 (x3 y10 (x3 x8 (x3 x9 (x3 x5 (x3 x6 y11))))))).
set y13 to be ...
set y14 to be ...
set y15 to be ...
Claim L11: ∀ x16 : ι → ο . x16 y15 ⟶ x16 y14
Let x16 of type ι → ο be given.
Assume H11: x16 (x5 x6 (x5 x12 (x5 y10 (x5 y11 (x5 x7 (x5 x8 y13)))))).
set y17 to be λ x17 . x16
set y18 to be λ x18 x19 . y17 (x5 x6 x18) (x5 x6 x19)
Apply unknownprop_6df806693864a23a378ddbca02cda4bb4bc233ff1daa8914d51c06eb72ff2550 with
x4,
x5,
x12,
y10,
y11,
x5 x7 (x5 x8 y13),
λ x19 x20 . y18 x20 x19 leaving 7 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H8.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
Apply H0 with
x7,
x5 x8 y13 leaving 2 subgoals.
The subproof is completed by applying H3.
Apply H0 with
x8,
y13 leaving 2 subgoals.
The subproof is completed by applying H4.
The subproof is completed by applying H9.
The subproof is completed by applying H11.
set y16 to be λ x16 x17 . y15 (x5 x9 x16) (x5 x9 x17)
Apply L11 with
λ x17 . y16 x17 y15 ⟶ y16 y15 x17 leaving 2 subgoals.
Assume H12: y16 y15 y15.
The subproof is completed by applying H12.
The subproof is completed by applying L11.
Let x12 of type ι → ι → ο be given.
Apply L10 with
λ x13 . x12 x13 y11 ⟶ x12 y11 x13.
Assume H11: x12 y11 y11.
The subproof is completed by applying H11.