Search for blocks/addresses/...

Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιιι be given.
Assume H0: ∀ x2 . In x2 x0∀ x3 . In x3 x0In (x1 x2 x3) x0.
Let x2 of type ιιιι be given.
Assume H1: ∀ x3 . In x3 x0∀ x4 . In x4 x0∀ x5 . In x5 x0In (x2 x3 x4 x5) x0.
Let x3 of type ι be given.
Assume H2: In x3 x0.
Let x4 of type ι be given.
Assume H3: In x4 x0.
Let x5 of type ι be given.
Assume H4: In x5 x0.
Let x6 of type ιιι be given.
Assume H5: ∀ x7 . In x7 x0∀ x8 . In x8 x0In (x6 x7 x8) x0.
Let x7 of type ι be given.
Assume H6: In x7 x0.
Let x8 of type ιιι be given.
Assume H7: ∀ x9 . In x9 x0∀ x10 . In x10 x0In (x8 x9 x10) x0.
Assume H8: ∀ x9 . In x9 x0(x8 x7 x9 = x9False)False.
Assume H9: ∀ x9 . In x9 x0∀ x10 . In x10 x0(x1 x9 (x8 x9 x10) = x10False)False.
Assume H10: ∀ x9 . In x9 x0∀ x10 . In x10 x0(x8 x9 (x1 x9 x10) = x10False)False.
Assume H11: ∀ x9 . In x9 x0∀ x10 . In x10 x0∀ x11 . In x11 x0(x2 x9 x10 x11 = x1 (x8 x10 x9) (x8 x10 (x8 x9 x11))False)False.
Assume H12: ∀ x9 . In x9 x0(x6 x7 x9 = x9False)False.
Assume H13: ∀ x9 . In x9 x0∀ x10 . In x10 x0∀ x11 . In x11 x0∀ x12 . In x12 x0(x2 x9 x11 (x6 x10 (x2 x9 x11 (x6 x10 (x2 x9 x11 (x6 x10 (x2 x9 x11 (x6 x10 x12))))))) = x12False)False.
Assume H14: ∀ x9 . In x9 x0∀ x10 . In x10 x0∀ x11 . In x11 x0(x2 x9 x10 (x6 x9 (x6 x10 (x2 x9 x10 (x6 x9 (x6 x10 (x2 x9 x10 (x6 x9 (x6 x10 x11)))))))) = x11False)False.
Assume H15: x8 (x8 x5 x4) x3 = x8 x5 (x8 ... ...)False.
...