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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: 80242.. x0.
Assume H1: 80242.. x1.
Apply unknownprop_0aeb103bb8c1020fd1bbf8133fbf92076b19ca29b614a77dbfc670876f391329 with 236dc.. x0 x1, ce322.. (236dc.. x0 x1) = x0 leaving 2 subgoals.
Apply unknownprop_a11dfa210cd480918339ec3ee480411b7f4945c0aeef474c01ca879d15816c74 with x0, x1 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Assume H2: 80242.. (ce322.. (236dc.. x0 x1)).
Assume H3: ∃ x2 . and (80242.. x2) (236dc.. x0 x1 = 236dc.. (ce322.. (236dc.. x0 x1)) x2).
Apply H3 with ce322.. (236dc.. x0 x1) = x0.
Let x2 of type ι be given.
Assume H4: (λ x3 . and (80242.. x3) (236dc.. x0 x1 = 236dc.. (ce322.. (236dc.. x0 x1)) x3)) x2.
Apply H4 with ce322.. (236dc.. x0 x1) = x0.
Assume H5: 80242.. x2.
Assume H6: 236dc.. x0 x1 = 236dc.. (ce322.. (236dc.. x0 x1)) x2.
Let x3 of type ιιο be given.
Apply unknownprop_20aee288fe544593cb730f361570be2fc95d6b53d7a983cf10cd18dc24e2d96a with x0, x1, ce322.. (236dc.. x0 x1), x2, λ x4 x5 . x3 x5 x4 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
The subproof is completed by applying H6.