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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιι be given.
Let x2 of type ι be given.
Apply unknownprop_17fe3de18bc1fbdc28d994143167b7a573f559855ba378d2014a681d31fa93ad with λ x3 x4 : ι → (ι → ι) → ι . In x2 (x4 x0 (λ x5 . x1 x5))and (and (setsum (proj0 x2) (proj1 x2) = x2) (In (proj0 x2) x0)) (In (proj1 x2) (x1 (proj0 x2))).
Assume H0: In x2 (famunion x0 (λ x3 . Repl (x1 x3) (λ x4 . setsum x3 x4))).
Apply unknownprop_a7f2dda18b84bce65b5de34328a937fef2c23812675d88bde1e7e2463ed59bbe with x0, λ x3 . Repl (x1 x3) (λ x4 . setsum x3 x4), x2, and (and (setsum (proj0 x2) (proj1 x2) = x2) (In (proj0 x2) x0)) (In (proj1 x2) (x1 (proj0 x2))) leaving 2 subgoals.
The subproof is completed by applying H0.
Let x3 of type ι be given.
Assume H1: In x3 x0.
Assume H2: In x2 (Repl (x1 x3) (λ x4 . setsum x3 x4)).
Apply unknownprop_89e422bb3b8a01dd209d7f2f210df650a435fc3e6005e0f59c57a5e7a59a6d0e with x1 x3, setsum x3, x2, and (and (setsum (proj0 x2) (proj1 x2) = x2) (In (proj0 x2) x0)) (In (proj1 x2) (x1 (proj0 x2))) leaving 2 subgoals.
The subproof is completed by applying H2.
Let x4 of type ι be given.
Assume H3: In x4 (x1 x3).
Assume H4: x2 = setsum x3 x4.
Apply H4 with λ x5 x6 . and (and (setsum (proj0 x6) (proj1 x6) = x6) (In (proj0 x6) x0)) (In (proj1 x6) (x1 (proj0 x6))).
Apply unknownprop_e2d9dae0ea3a0bd6555cf6ae3b66e91e8730bfc402bf8dbafcc7b19c9adfb426 with x3, x4, λ x5 x6 . and (and (setsum x6 (proj1 (setsum x3 x4)) = setsum x3 x4) (In x6 x0)) (In (proj1 (setsum x3 x4)) (x1 x6)).
Apply unknownprop_d4bb68cbfba730ad1b1ee2c6901fadf3c573cb615fac3296f9bb52128e37668a with x3, x4, λ x5 x6 . and (and (setsum x3 x6 = setsum x3 x4) (In x3 x0)) (In x6 (x1 x3)).
Apply unknownprop_c7bf67064987d41cefc55afb6af6ecbbb6b830405f2005e0def6e504b3ca3bf3 with setsum x3 x4 = setsum x3 x4, In x3 x0, In x4 (x1 x3) leaving 3 subgoals.
Let x5 of type ιιο be given.
Assume H5: x5 (setsum x3 x4) (setsum x3 x4).
The subproof is completed by applying H5.
The subproof is completed by applying H1.
The subproof is completed by applying H3.