Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Assume H2: x2 ∈ x0.
Let x3 of type ι be given.
Assume H3: x3 ∈ x1.
Apply ordinal_Hered with
x0,
x2 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
Apply ordinal_Hered with
x1,
x3 leaving 2 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
Apply ordinal_SNoLt_In with
add_SNo (mul_SNo x2 x1) (mul_SNo x0 x3),
add_SNo (mul_SNo x0 x1) (mul_SNo x2 x3) leaving 3 subgoals.
Apply add_SNo_ordinal_ordinal with
mul_SNo x2 x1,
mul_SNo x0 x3 leaving 2 subgoals.
Apply mul_SNo_ordinal_ordinal with
x2,
x1 leaving 2 subgoals.
The subproof is completed by applying L4.
The subproof is completed by applying H1.
Apply mul_SNo_ordinal_ordinal with
x0,
x3 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying L5.
Apply add_SNo_ordinal_ordinal with
mul_SNo x0 x1,
mul_SNo x2 x3 leaving 2 subgoals.
Apply mul_SNo_ordinal_ordinal with
x0,
x1 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Apply mul_SNo_ordinal_ordinal with
x2,
x3 leaving 2 subgoals.
The subproof is completed by applying L4.
The subproof is completed by applying L5.
Apply mul_SNo_Lt with
x0,
x1,
x2,
x3 leaving 6 subgoals.
Apply ordinal_SNo with
x0.
The subproof is completed by applying H0.
Apply ordinal_SNo with
x1.
The subproof is completed by applying H1.
Apply ordinal_SNo with
x2.
The subproof is completed by applying L4.
Apply ordinal_SNo with
x3.
The subproof is completed by applying L5.
Apply ordinal_In_SNoLt with
x0,
x2 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
Apply ordinal_In_SNoLt with
x1,
x3 leaving 2 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H3.