Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Apply beta with
6,
λ x6 . If_i (x6 = 0) x0 (If_i (x6 = 1) x1 (If_i (x6 = 2) x2 (If_i (x6 = 3) x3 (If_i (x6 = 4) x4 x5)))),
4,
λ x6 x7 . x7 = x4 leaving 2 subgoals.
The subproof is completed by applying In_4_6.
Apply If_i_0 with
4 = 0,
x0,
If_i (4 = 1) x1 (If_i (4 = 2) x2 (If_i (4 = 3) x3 (If_i (4 = 4) x4 x5))),
λ x6 x7 . x7 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_0.
Apply If_i_0 with
4 = 1,
x1,
If_i (4 = 2) x2 (If_i (4 = 3) x3 (If_i (4 = 4) x4 x5)),
λ x6 x7 . x7 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_1.
Apply If_i_0 with
4 = 2,
x2,
If_i (4 = 3) x3 (If_i (4 = 4) x4 x5),
λ x6 x7 . x7 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_2.
Apply If_i_0 with
4 = 3,
x3,
If_i (4 = 4) x4 x5,
λ x6 x7 . x7 = x4 leaving 2 subgoals.
The subproof is completed by applying neq_4_3.
Apply If_i_1 with
4 = 4,
x4,
x5.
Let x6 of type ι → ι → ο be given.
Assume H0: x6 4 4.
The subproof is completed by applying H0.