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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιι be given.
Assume H0: ∀ x2 x3 . x0 x2x0 x3x0 (x1 x2 x3).
Assume H1: ∀ x2 x3 x4 . x0 x2x0 x3x0 x4x1 (x1 x2 x3) x4 = x1 x2 (x1 x3 x4).
Let x2 of type ι be given.
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Assume H2: x0 x2.
Assume H3: x0 x3.
Assume H4: x0 x4.
Assume H5: x0 x5.
Assume H6: x0 x6.
Apply H1 with x2, x1 x3 (x1 x4 x5), x6, λ x7 x8 . x8 = x1 x2 (x1 x3 (x1 x4 (x1 x5 x6))) leaving 4 subgoals.
The subproof is completed by applying H2.
Apply unknownprop_a6006624829d7d44dfef146f097f47f429351018787d2b11ce9751df54eb1332 with x0, x1, x3, x4, x5 leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
set y7 to be x1 x2 (x1 (x1 x3 (x1 x4 x5)) x6)
set y8 to be x2 x3 (x2 x4 (x2 x5 (x2 x6 y7)))
Claim L7: ∀ x9 : ι → ο . x9 y8x9 y7
Let x9 of type ιο be given.
Assume H7: x9 (x3 x4 (x3 x5 (x3 x6 (x3 y7 y8)))).
set y10 to be λ x10 . x9
Apply unknownprop_77decf6bf1332e51bcea19ab2a61784f9a76d4bc1da5ba5642776f807627043b with x2, x3, x5, x6, y7, y8, λ x11 x12 . y10 (x3 x4 x11) (x3 x4 x12) leaving 7 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
Let x9 of type ιιο be given.
Apply L7 with λ x10 . x9 x10 y8x9 y8 x10.
Assume H8: x9 y8 y8.
The subproof is completed by applying H8.