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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Assume H0: x1int.
Let x2 of type ι be given.
Assume H1: x2int.
Let x3 of type ι be given.
Assume H2: x3int.
Let x4 of type ι be given.
Assume H3: x4int.
Assume H4: divides_int x0 (add_SNo x2 (minus_SNo x3)).
Apply add_SNo_com_3_0_1 with x1, x3, x4, λ x5 x6 . divides_int x0 x6divides_int x0 (add_SNo x1 (add_SNo x2 x4)) leaving 4 subgoals.
Apply int_SNo with x1.
The subproof is completed by applying H0.
Apply int_SNo with x3.
The subproof is completed by applying H2.
Apply int_SNo with x4.
The subproof is completed by applying H3.
Apply add_SNo_com_3_0_1 with x1, x2, x4, λ x5 x6 . divides_int x0 (add_SNo x3 (add_SNo x1 x4))divides_int x0 x6 leaving 4 subgoals.
Apply int_SNo with x1.
The subproof is completed by applying H0.
Apply int_SNo with x2.
The subproof is completed by applying H1.
Apply int_SNo with x4.
The subproof is completed by applying H3.
Apply unknownprop_82d8b16cbabe15f33566315da037f391b292861be9631cc7d9815c42bac38696 with x0, x2, x3, add_SNo x1 x4 leaving 4 subgoals.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
Apply int_add_SNo with x1, x4 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H3.
The subproof is completed by applying H4.