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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιιι be given.
Assume H0: explicit_Group x0 x1.
Let x2 of type ι be given.
Assume H1: x2x0.
Apply explicit_Group_inverse_prop with x0, x1, x2, x1 x2 (explicit_Group_inverse x0 x1 x2) = explicit_Group_identity x0 x1 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Assume H2: explicit_Group_inverse x0 x1 x2x0.
Assume H3: and (x1 x2 (explicit_Group_inverse x0 x1 x2) = explicit_Group_identity x0 x1) (x1 (explicit_Group_inverse x0 x1 x2) x2 = explicit_Group_identity x0 x1).
Apply H3 with x1 x2 (explicit_Group_inverse x0 x1 x2) = explicit_Group_identity x0 x1.
Assume H4: x1 x2 (explicit_Group_inverse x0 x1 x2) = explicit_Group_identity x0 x1.
Assume H5: x1 (explicit_Group_inverse x0 x1 x2) x2 = explicit_Group_identity x0 x1.
The subproof is completed by applying H4.