Let x0 of type ι be given.
Let x1 of type ι be given.
Apply H0 with
SNoCutP {minus_SNo x2|x2 ∈ x1} {minus_SNo x2|x2 ∈ x0}.
Assume H1:
and (∀ x2 . x2 ∈ x0 ⟶ SNo x2) (∀ x2 . x2 ∈ x1 ⟶ SNo x2).
Apply H1 with
(∀ x2 . x2 ∈ x0 ⟶ ∀ x3 . x3 ∈ x1 ⟶ SNoLt x2 x3) ⟶ SNoCutP {minus_SNo x2|x2 ∈ x1} {minus_SNo x2|x2 ∈ x0}.
Assume H2:
∀ x2 . x2 ∈ x0 ⟶ SNo x2.
Assume H3:
∀ x2 . x2 ∈ x1 ⟶ SNo x2.
Assume H4:
∀ x2 . x2 ∈ x0 ⟶ ∀ x3 . x3 ∈ x1 ⟶ SNoLt x2 x3.
Apply and3I with
∀ x2 . x2 ∈ {minus_SNo x3|x3 ∈ x1} ⟶ SNo x2,
∀ x2 . x2 ∈ {minus_SNo x3|x3 ∈ x0} ⟶ SNo x2,
∀ x2 . x2 ∈ {minus_SNo x3|x3 ∈ x1} ⟶ ∀ x3 . x3 ∈ {minus_SNo x4|x4 ∈ x0} ⟶ SNoLt x2 x3 leaving 3 subgoals.
Let x2 of type ι be given.
Assume H5:
x2 ∈ {minus_SNo x3|x3 ∈ x1}.
Apply ReplE_impred with
x1,
λ x3 . minus_SNo x3,
x2,
SNo x2 leaving 2 subgoals.
The subproof is completed by applying H5.
Let x3 of type ι be given.
Assume H6: x3 ∈ x1.
Apply H7 with
λ x4 x5 . SNo x5.
Apply SNo_minus_SNo with
x3.
Apply H3 with
x3.
The subproof is completed by applying H6.
Let x2 of type ι be given.
Assume H5:
x2 ∈ {minus_SNo x3|x3 ∈ x0}.
Apply ReplE_impred with
x0,
λ x3 . minus_SNo x3,
x2,
SNo x2 leaving 2 subgoals.
The subproof is completed by applying H5.
Let x3 of type ι be given.
Assume H6: x3 ∈ x0.
Apply H7 with
λ x4 x5 . SNo x5.
Apply SNo_minus_SNo with
x3.
Apply H2 with
x3.
The subproof is completed by applying H6.
Let x2 of type ι be given.
Assume H5:
x2 ∈ {minus_SNo x3|x3 ∈ x1}.
Let x3 of type ι be given.
Assume H6:
x3 ∈ {minus_SNo x4|x4 ∈ x0}.
Apply ReplE_impred with
x1,
λ x4 . minus_SNo x4,
x2,
SNoLt x2 x3 leaving 2 subgoals.
The subproof is completed by applying H5.
Let x4 of type ι be given.
Assume H7: x4 ∈ x1.
Apply ReplE_impred with
x0,
λ x5 . minus_SNo x5,
x3,
SNoLt x2 x3 leaving 2 subgoals.
The subproof is completed by applying H6.
Let x5 of type ι be given.
Assume H9: x5 ∈ x0.
Apply H8 with
λ x6 x7 . SNoLt x7 x3.
Apply H10 with
λ x6 x7 . SNoLt (minus_SNo x4) x7.
Apply minus_SNo_Lt_contra with
x5,
x4 leaving 3 subgoals.
Apply H2 with
x5.
The subproof is completed by applying H9.
Apply H3 with
x4.
The subproof is completed by applying H7.
Apply H4 with
x5,
x4 leaving 2 subgoals.
The subproof is completed by applying H9.
The subproof is completed by applying H7.