Let x0 of type ι → ο be given.
Let x1 of type ι → ι → ι be given.
Let x2 of type ι → ι → ι be given.
Assume H0: ∀ x3 x4 . x0 x3 ⟶ x0 x4 ⟶ x0 (x1 x3 x4).
Assume H1: ∀ x3 x4 x5 . x0 x3 ⟶ x0 x4 ⟶ x0 x5 ⟶ x2 x3 (x1 x4 x5) = x1 (x2 x3 x4) (x2 x3 x5).
Assume H2: ∀ x3 x4 x5 . x0 x3 ⟶ x0 x4 ⟶ x0 x5 ⟶ x2 (x1 x3 x4) x5 = x1 (x2 x3 x5) (x2 x4 x5).
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Let x10 of type ι be given.
Let x11 of type ι be given.
Let x12 of type ι be given.
Let x13 of type ι be given.
Let x14 of type ι be given.
Assume H3: x0 x3.
Assume H4: x0 x4.
Assume H5: x0 x5.
Assume H6: x0 x6.
Assume H7: x0 x7.
Assume H8: x0 x8.
Assume H9: x0 x9.
Assume H10: x0 x10.
Assume H11: x0 x11.
Assume H12: x0 x12.
Assume H13: x0 x13.
Assume H14: x0 x14.
Apply unknownprop_55de5c79fadd89ca3e161a61e8ef1cc68aeee5eba6c4fec4d11d6eacbce11bf5 with
x0,
x1,
x2,
x3,
x4,
x5,
x6,
x7,
x1 x8 (x1 x9 (x1 x10 (x1 x11 (x1 x12 (x1 x13 x14))))),
λ x15 x16 . x16 = x1 (x1 (x2 x3 x8) (x1 (x2 x3 x9) (x1 (x2 x3 x10) (x1 (x2 x3 x11) (x1 (x2 x3 x12) (x1 (x2 x3 x13) (x2 x3 x14))))))) (x1 (x1 (x2 x4 x8) (x1 (x2 x4 x9) (x1 (x2 x4 x10) (x1 (x2 x4 x11) (x1 (x2 x4 x12) (x1 (x2 x4 x13) (x2 x4 x14))))))) (x1 (x1 (x2 x5 x8) (x1 (x2 x5 x9) (x1 (x2 x5 x10) (x1 (x2 x5 x11) (x1 (x2 x5 x12) (x1 (x2 x5 x13) (x2 x5 x14))))))) (x1 (x1 (x2 x6 x8) (x1 (x2 x6 x9) (x1 (x2 x6 x10) (x1 (x2 x6 x11) (x1 (x2 x6 x12) (x1 (x2 x6 x13) (x2 x6 x14))))))) (x1 (x2 x7 x8) (x1 (x2 x7 x9) (x1 (x2 x7 x10) (x1 (x2 x7 x11) (x1 (x2 x7 x12) (x1 (x2 x7 x13) (x2 x7 x14)))))))))) leaving 9 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H7.
Apply unknownprop_025d233877239fdf8667e3ba4d630729f1334dc236b8bf7cefec04c2fd303300 with
x0,
x1,
...,
...,
...,
...,
...,
...,
... leaving 8 subgoals.