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Proofgold Proof

pf
Let x0 of type ι be given.
Assume H0: 80242.. x0.
Let x1 of type ο be given.
Assume H1: ∀ x2 . and (80242.. x2) (∃ x3 . and (80242.. x3) (x0 = 236dc.. x2 x3))x1.
Apply H1 with x0.
Apply andI with 80242.. x0, ∃ x2 . and (80242.. x2) (x0 = 236dc.. x0 x2) leaving 2 subgoals.
The subproof is completed by applying H0.
Let x2 of type ο be given.
Assume H2: ∀ x3 . and (80242.. x3) (x0 = 236dc.. x0 x3)x2.
Apply H2 with 4a7ef...
Apply andI with 80242.. 4a7ef.., x0 = 236dc.. x0 4a7ef.. leaving 2 subgoals.
The subproof is completed by applying unknownprop_a66a65189a5389c2141d18df52f52fcf5f074fba68040a0bda3b8b81c830611a.
Let x3 of type ιιο be given.
The subproof is completed by applying unknownprop_8caab58746e5d2d24e79c56b1fd1ad38271bed0128653f24088edadc36aa9114 with x0, λ x4 x5 . x3 x5 x4.