Let x0 of type ι → ο be given.
Let x1 of type ι → ι → ι be given.
Let x2 of type ι → ι → ι be given.
Assume H0: ∀ x3 x4 . x0 x3 ⟶ x0 x4 ⟶ x0 (x1 x3 x4).
Assume H1: ∀ x3 x4 x5 . x0 x3 ⟶ x0 x4 ⟶ x0 x5 ⟶ x2 x3 (x1 x4 x5) = x1 (x2 x3 x4) (x2 x3 x5).
Assume H2: ∀ x3 x4 x5 . x0 x3 ⟶ x0 x4 ⟶ x0 x5 ⟶ x2 (x1 x3 x4) x5 = x1 (x2 x3 x5) (x2 x4 x5).
Let x3 of type ι be given.
Let x4 of type ι be given.
Let x5 of type ι be given.
Let x6 of type ι be given.
Let x7 of type ι be given.
Let x8 of type ι be given.
Let x9 of type ι be given.
Let x10 of type ι be given.
Assume H3: x0 x3.
Assume H4: x0 x4.
Assume H5: x0 x5.
Assume H6: x0 x6.
Assume H7: x0 x7.
Assume H8: x0 x8.
Assume H9: x0 x9.
Assume H10: x0 x10.
Apply unknownprop_f8cd2cc9fa3527ece23bf769ef6e4562a4db8193110bd03a6fde0a07ab4c38b8 with
x0,
x1,
x2,
x3,
x4,
x5,
x6,
x1 x7 (x1 x8 (x1 x9 x10)),
λ x11 x12 . x12 = x1 (x1 (x2 x3 x7) (x1 (x2 x3 x8) (x1 (x2 x3 x9) (x2 x3 x10)))) (x1 (x1 (x2 x4 x7) (x1 (x2 x4 x8) (x1 (x2 x4 x9) (x2 x4 x10)))) (x1 (x1 (x2 x5 x7) (x1 (x2 x5 x8) (x1 (x2 x5 x9) (x2 x5 x10)))) (x1 (x2 x6 x7) (x1 (x2 x6 x8) (x1 (x2 x6 x9) (x2 x6 x10)))))) leaving 8 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
Apply unknownprop_b48d4480a5526e51a91293fec1b0b9440be4280265441ce358bda14cced12479 with
x0,
x1,
x7,
x8,
x9,
x10 leaving 5 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H7.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H10.
Apply unknownprop_483ab2c4cf352794c6e764ca83196651bc5de6ef598ec843402a4c02baafb47b with
x0,
x1,
x2,
x7,
x8,
x9,
x10,
x3,
λ x11 x12 . x1 x12 (x1 (x2 x4 (x1 x7 (x1 x8 (x1 x9 x10)))) (x1 (x2 x5 (x1 x7 (x1 x8 (x1 x9 x10)))) (x2 x6 (x1 x7 (x1 x8 (x1 x9 x10)))))) = x1 (x1 (x2 x3 x7) (x1 (x2 x3 x8) (x1 (x2 x3 x9) (x2 x3 x10)))) (x1 (x1 (x2 x4 x7) (x1 (x2 x4 x8) (x1 (x2 x4 x9) (x2 x4 x10)))) (x1 (x1 (x2 x5 x7) (x1 (x2 x5 x8) (x1 (x2 x5 x9) (x2 x5 x10)))) (x1 (x2 x6 x7) (x1 (x2 ... ...) ...)))) leaving 8 subgoals.