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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ιιο be given.
Assume H0: ∀ x2 . x2x0∀ x3 . x3x0x1 x2 x3x1 x3 x2.
Let x2 of type ι be given.
Assume H1: x2x0.
Let x3 of type ι be given.
Assume H2: x3x0.
Let x4 of type ι be given.
Assume H3: x4x0.
Let x5 of type ι be given.
Assume H4: x5x0.
Let x6 of type ι be given.
Assume H5: x6x0.
Let x7 of type ι be given.
Assume H6: x7x0.
Let x8 of type ι be given.
Assume H7: x8x0.
Assume H8: 58366.. x1 x2 x3 x4 x5 x6 x7 x8.
Let x9 of type ο be given.
Assume H9: 5e84d.. x1 x3 x2 x4 x5 x6 x7(x3 = x8∀ x10 : ο . x10)(x2 = x8∀ x10 : ο . x10)(x4 = x8∀ x10 : ο . x10)(x5 = x8∀ x10 : ο . x10)(x6 = x8∀ x10 : ο . x10)(x7 = x8∀ x10 : ο . x10)x1 x3 x8x1 x2 x8not (x1 x4 x8)not (x1 x5 x8)not (x1 x6 x8)not (x1 x7 x8)x9.
Apply H8 with x9.
Assume H10: 5e84d.. x1 x2 x3 x4 x5 x6 x7.
Assume H11: x2 = x8∀ x10 : ο . x10.
Assume H12: x3 = x8∀ x10 : ο . x10.
Assume H13: x4 = x8∀ x10 : ο . x10.
Assume H14: x5 = x8∀ x10 : ο . x10.
Assume H15: x6 = x8∀ x10 : ο . x10.
Assume H16: x7 = x8∀ x10 : ο . x10.
Assume H17: x1 x2 x8.
Assume H18: x1 x3 x8.
Assume H19: not (x1 x4 x8).
Assume H20: not (x1 x5 x8).
Assume H21: not (x1 x6 x8).
Assume H22: not (x1 x7 x8).
Apply H9 leaving 13 subgoals.
Apply unknownprop_c05dc5c509e1f92b8234d6e23675c80dd86d32981be20a6277b34f12801d25f7 with x0, x1, x2, x3, x4, x5, x6, x7 leaving 8 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
The subproof is completed by applying H4.
The subproof is completed by applying H5.
The subproof is completed by applying H6.
The subproof is completed by applying H10.
The subproof is completed by applying H12.
The subproof is completed by applying H11.
The subproof is completed by applying H13.
The subproof is completed by applying H14.
The subproof is completed by applying H15.
The subproof is completed by applying H16.
The subproof is completed by applying H18.
The subproof is completed by applying H17.
The subproof is completed by applying H19.
The subproof is completed by applying H20.
The subproof is completed by applying H21.
The subproof is completed by applying H22.