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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ι be given.
Let x3 of type ι be given.
Assume H0: SNo x0.
Assume H1: SNo x1.
Assume H2: SNo x2.
Assume H3: SNo x3.
Apply unknownprop_431ff8ff6435faa4c5f86e4f0a6c43deeb7869b72194a714b191972a3eaf6491 with f4b0e.. x0 x1 x2 x3, 6b27d.. (f4b0e.. x0 x1 x2 x3) = x0 leaving 2 subgoals.
Apply unknownprop_1c4b77a1bdf71ac8c46772d8b01bd6609e54ee74070e16498c4800adfe13c5ca with x0, x1, x2, x3 leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H3.
Assume H4: SNo (6b27d.. (f4b0e.. x0 x1 x2 x3)).
Assume H5: ∃ x4 . and (SNo x4) (∃ x5 . and (SNo x5) (∃ x6 . and (SNo x6) (f4b0e.. x0 x1 x2 x3 = f4b0e.. (6b27d.. (f4b0e.. x0 x1 x2 x3)) x4 x5 x6))).
Apply H5 with 6b27d.. (f4b0e.. x0 x1 x2 x3) = x0.
Let x4 of type ι be given.
Assume H6: (λ x5 . and (SNo x5) (∃ x6 . and (SNo x6) (∃ x7 . and (SNo x7) (f4b0e.. x0 x1 x2 x3 = f4b0e.. (6b27d.. (f4b0e.. x0 x1 x2 x3)) x5 x6 x7)))) x4.
Apply H6 with 6b27d.. (f4b0e.. x0 x1 x2 x3) = x0.
Assume H7: SNo x4.
Assume H8: ∃ x5 . and (SNo x5) (∃ x6 . and (SNo x6) (f4b0e.. x0 x1 x2 x3 = f4b0e.. (6b27d.. (f4b0e.. x0 x1 x2 x3)) x4 x5 x6)).
Apply H8 with 6b27d.. (f4b0e.. x0 x1 x2 x3) = x0.
Let x5 of type ι be given.
Assume H9: (λ x6 . and (SNo x6) (∃ x7 . and (SNo x7) (f4b0e.. x0 x1 x2 x3 = f4b0e.. (6b27d.. (f4b0e.. x0 x1 x2 x3)) x4 x6 x7))) x5.
Apply H9 with 6b27d.. (f4b0e.. x0 x1 x2 x3) = x0.
Assume H10: SNo x5.
Assume H11: ∃ x6 . and (SNo x6) (f4b0e.. x0 x1 x2 x3 = f4b0e.. (6b27d.. (f4b0e.. x0 x1 x2 x3)) x4 x5 x6).
Apply H11 with 6b27d.. (f4b0e.. x0 x1 x2 x3) = x0.
Let x6 of type ι be given.
Assume H12: (λ x7 . and (SNo x7) (f4b0e.. x0 x1 x2 x3 = f4b0e.. (6b27d.. (f4b0e.. x0 x1 x2 x3)) x4 x5 x7)) x6.
Apply H12 with 6b27d.. (f4b0e.. x0 x1 x2 x3) = x0.
Assume H13: SNo x6.
Assume H14: f4b0e.. x0 x1 x2 x3 = f4b0e.. (6b27d.. (f4b0e.. x0 x1 x2 x3)) ... ... ....
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