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Proofgold Proof

pf
Let x0 of type ιο be given.
Let x1 of type ιιι be given.
Let x2 of type ιιι be given.
Assume H0: ∀ x3 x4 . x0 x3x0 x4x0 (x1 x3 x4).
Assume H1: ∀ x3 x4 x5 . x0 x3x0 x4x0 x5x2 (x1 x3 x4) x5 = x1 (x2 x3 x5) (x2 x4 x5).
Assume H2: ∀ x3 x4 x5 . x0 x3x0 x4x0 x5x2 x3 (x1 x4 x5) = x1 (x2 x3 x4) (x2 x3 x5).
Let x3 of type ιι be given.
Assume H3: ∀ x4 . x0 x4x0 (x3 x4).
Assume H4: ∀ x4 x5 . x0 x4x0 x5x0 (x2 x4 x5).
Assume H5: ∀ x4 x5 . x0 x4x0 x5x2 x4 x5 = x2 x5 x4.
Assume H6: ∀ x4 x5 . x0 x4x0 x5x2 x4 (x3 x5) = x3 (x2 x4 x5).
Assume H7: ∀ x4 x5 x6 . x0 x4x0 x5x0 x6x1 (x1 x4 (x3 x5)) (x1 x5 x6) = x1 x4 x6.
Let x4 of type ι be given.
Let x5 of type ι be given.
Assume H8: x0 x4.
Assume H9: x0 x5.
Apply unknownprop_72d123fd4d496da4fbf16cba456f7da0b762c033cc9f0bd9adf4e316000f1ad6 with x0, x1, x2, x4, x5, x4, x3 x5, λ x6 x7 . x7 = x1 ((λ x8 . x2 x8 x8) x4) (x3 (x2 x5 x5)) leaving 8 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H2.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
The subproof is completed by applying H8.
Apply H3 with x5.
The subproof is completed by applying H9.
Apply H5 with x5, x4, λ x6 x7 . x1 (x1 ((λ x8 . x2 x8 x8) x4) (x2 x4 (x3 x5))) (x1 x7 (x2 x5 (x3 x5))) = x1 ((λ x8 . x2 x8 x8) x4) (x3 ((λ x8 . x2 x8 x8) x5)) leaving 3 subgoals.
The subproof is completed by applying H9.
The subproof is completed by applying H8.
Apply H6 with x4, x5, λ x6 x7 . x1 (x1 ((λ x8 . x2 x8 x8) x4) x7) (x1 (x2 x4 x5) (x2 x5 (x3 x5))) = x1 ((λ x8 . x2 x8 x8) x4) (x3 ((λ x8 . x2 x8 x8) x5)) leaving 3 subgoals.
The subproof is completed by applying H8.
The subproof is completed by applying H9.
Apply H6 with x5, x5, λ x6 x7 . x1 (x1 ((λ x8 . x2 x8 x8) x4) (x3 (x2 x4 x5))) (x1 (x2 x4 x5) x7) = x1 ((λ x8 . x2 x8 x8) x4) (x3 ((λ x8 . x2 x8 x8) x5)) leaving 3 subgoals.
The subproof is completed by applying H9.
The subproof is completed by applying H9.
Apply H7 with (λ x6 . x2 x6 x6) x4, x2 x4 x5, x3 ((λ x6 . x2 x6 x6) x5) leaving 3 subgoals.
Apply H4 with x4, x4 leaving 2 subgoals.
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