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Proofgold Proof

pf
Let x0 of type ι be given.
Let x1 of type ι be given.
Let x2 of type ιι be given.
Let x3 of type ι be given.
Let x4 of type ιιι be given.
Assume H0: explicit_Nats x0 x1 x2.
Apply explicit_Nats_ind with x0, x1, x2, λ x5 . ∀ x6 x7 . c3e2e.. x0 x1 x2 x3 x4 x5 x6c3e2e.. x0 x1 x2 x3 x4 x5 x7x6 = x7 leaving 3 subgoals.
The subproof is completed by applying H0.
Let x5 of type ι be given.
Let x6 of type ι be given.
Assume H1: c3e2e.. x0 x1 x2 x3 x4 x1 x5.
Assume H2: c3e2e.. x0 x1 x2 x3 x4 x1 x6.
Apply unknownprop_987d3840aa104d50ea50759bc446be3aae0e33c59dc8291c7942424d9287e6ed with x0, x1, x2, x3, x4, x6, λ x7 x8 . x5 = x8 leaving 3 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H2.
Apply unknownprop_987d3840aa104d50ea50759bc446be3aae0e33c59dc8291c7942424d9287e6ed with x0, x1, x2, x3, x4, x5 leaving 2 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
Let x5 of type ι be given.
Assume H1: x5x0.
Assume H2: ∀ x6 x7 . c3e2e.. x0 x1 x2 x3 x4 x5 x6c3e2e.. x0 x1 x2 x3 x4 x5 x7x6 = x7.
Let x6 of type ι be given.
Let x7 of type ι be given.
Assume H3: c3e2e.. x0 x1 x2 x3 x4 (x2 x5) x6.
Assume H4: c3e2e.. x0 x1 x2 x3 x4 (x2 x5) x7.
Apply unknownprop_2611cf16ddfa1b4edb79e3ab7434c5739866f2053fe5690c0b558b5b0ae50bfd with x0, x1, x2, x3, x4, x5, x6, x6 = x7 leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H3.
Let x8 of type ι be given.
Assume H5: (λ x9 . and (x6 = x4 x5 x9) (c3e2e.. x0 x1 x2 x3 x4 x5 x9)) x8.
Apply H5 with x6 = x7.
Assume H6: x6 = x4 x5 x8.
Assume H7: c3e2e.. x0 x1 x2 x3 x4 x5 x8.
Apply unknownprop_2611cf16ddfa1b4edb79e3ab7434c5739866f2053fe5690c0b558b5b0ae50bfd with x0, x1, x2, x3, x4, x5, x7, x6 = x7 leaving 4 subgoals.
The subproof is completed by applying H0.
The subproof is completed by applying H1.
The subproof is completed by applying H4.
Let x9 of type ι be given.
Assume H8: (λ x10 . and (x7 = x4 x5 x10) (c3e2e.. x0 x1 x2 x3 x4 x5 x10)) x9.
Apply H8 with x6 = x7.
Assume H9: x7 = x4 x5 x9.
Assume H10: c3e2e.. x0 x1 x2 x3 x4 x5 x9.
Apply H6 with λ x10 x11 . x11 = x7.
Apply H9 with λ x10 x11 . x4 x5 x8 = x11.
set y10 to be x4 x5 x8
set y11 to be x5 x6 y10
Claim L11: ∀ x12 : ι → ο . x12 y11x12 y10
Let x12 of type ιο be given.
Assume H11: x12 (x6 x7 y11).
set y13 to be λ x13 . x12
Apply H2 with y10, y11, λ x14 x15 . y13 (x6 x7 x14) (x6 x7 x15) leaving 3 subgoals.
The subproof is completed by applying H7.
The subproof is completed by applying H10.
The subproof is completed by applying H11.
Let x12 of type ιιο be given.
Apply L11 with λ x13 . x12 x13 y11x12 y11 x13.
Assume H12: x12 y11 y11.
The subproof is completed by applying H12.